Answer:
The energies of combustion (per gram) for hydrogen and methane are as follows: Methane = 82.5 kJ/g; Hydrogen = 162 kJ/g
<em>Note: The question is incomplete. The complete question is given below:</em>
To compare the energies of combustion of these fuels, the following experiment was carried out using a bomb calorimeter with a heat capacity of 11.3 kJ/℃. When a 1.00-g sample of methane gas burned with
<em>excess oxygen in the calorimeter, the temperature increased by 7.3℃. When a 1.00 g sample of hydrogen gas was burned with excess oxygen, the temperature increase was 14.3°C. Compare the energies of combustion (per gram) for hydrogen and methane.</em>
Explanation:
From the equation of the first law of thermodynamics, ΔU = Q + W
Since there is no expansion work in the bomb calorimeter, ΔU = Q
But Q = CΔT
where C is heat capacity of the bomb calorimeter = 11.3
kJ/ºC; ΔT = temperature change
For combustion of methane gas:
Q per gram = (
11.3
kJ/ºC * 7.3°C)/1.0g
Q = 83 kJ/g
For combustion of hydrogen gas:
Q per gram = (
11.3
kJ/ºC * 14.3°C)/1.0g
Q = 162 kJ/g
Contractions of the skeletal muscles
As it puts pressure and moves the blood along
You didn’t post the whole question :/
Answer : Option A)
45.5%
Explanation : We use the formula of calculating energy efficiency which is as,
η (in %)= [
] X 100
where η is energy efficiency,
and P values are for energy out and in.
So plugging the given values, we get,
η (in %) = (11825.5 / 25978.8) X 100 =
45.5 %
Answer:
The protons and electrons in each element are equal. The sulfur has 16 electrons and 16 protons. But the ionic atom's electron quantity changes depending on how many it has gained. 'S2-' has gained 2 electrons, which means it has now 18 electrons and 16 protons. 16 neutrons
Explanation:
