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adelina 88 [10]
4 years ago
14

Area immediately surrounding a hazardous material incident which extends far enough to protect personnel outside the zone from c

ontamination.
Chemistry
1 answer:
Paraphin [41]4 years ago
7 0
Protective Action Zone is the range instantly neighboring and downwind from the underlying seclusion zone; this zone is in inevitable risk of being defiled via airborne vapors inside 30 minutes of material discharge. Physically securing and keeping up the crisis scene by building up borders and defensive activity zones and denying section to unapproved people.
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An electron confined in a one-dimensional box is observed, at different times, to have energies of 12 eV, 27 eV, and 48 eV. What
Fynjy0 [20]

Answer:

l=3.5*10^{-10}m

Explanation:

From the question we are told that:

1st Energy     E_1=12eV=4(3eV)

2nd Energy  E_2=27eV=9(3eV)

3rd Energy   E_3=48eV=16(3eV)

 

Generally the equation for Energy E for electron in one dimensional box at ground state E_0 is mathematically given by

  E_0=\frac{h}{8ml^2}

  E_0=\frac{h}{8ml^2}

Therefore Length a is mathematically given as

l=\sqrt{\frac{h^2}{8mE_0} }

l=\sqrt{\frac{(6.625*10^{-34})^2}{8(9.1*19^{-31}{(3eV(1.6*10^{-19}))}}

l=3.5*10^{-10}m

8 0
3 years ago
The density of osmium, which is the densest metal, is 22.57 g/cm^3. What is the mass of a block of osmium that measures 1.00 cm
olganol [36]
Density = Mass / Volume
V = 1.00 * 4.00 * 2.50 = 10 cm³
22.57 g/cm³ = Mass / 10 cm³
M = 22.57 g/cm³ * 10 cm³
M = 225.7 g
Answer: The mass of the block of osmium is 225.7 g.
7 0
3 years ago
Read 2 more answers
How many grams are in 5.00 moles of sodium carbonate?
dimulka [17.4K]

Answer:

= 529.9422

grams

Explanation:

5  moles Sodium Carbonate

= 529.9422

grams

8 0
3 years ago
A scientist in London and a scientist in California both conducted independent investigations that produced similar results. Wha
VashaNatasha [74]
Then the data had to be the same.
6 0
3 years ago
Read 2 more answers
Nitrogen dioxide and water react to form nitric acid and nitrogen monoxide, like this:
dybincka [34]

Answer:

0.29

Explanation:

Step 1: Write the balanced equation at equilibrium

3 NO₂(g) + H₂O(l) ⇄ 2 HNO₃(aq) +  NO(g)

Step 2: Calculate the molar concentration of the substances

We will not calculate the molarity of H₂O because pure liquids are not included in the equilibrium constant. We will use the following expression.

Molarity = mass of solute / molar mass of solute × liters of solution

Since the volume of the vessel is missing, we will assume it is 1 L to see the procedure.

[NO₂] = 22.5 / 46.01 g/mol × 1 L = 0.489 M

[HNO₃] = 15.5 g / 63.01 g/mol × 1 L = 0.246 M

[NO] = 16.6 g / 30.01 g/mol × 1 L = 0.553 M

Step 3: Calculate the value of the equilibrium constant Kc for this reaction

Kc = [HNO₃]² × [NO] / [NO₂]³

Kc = 0.246² × 0.553 / 0.489³

Kc = 0.29

7 0
3 years ago
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