Answer:
No there is no displacement observed so no work done
Answer:
Explanation:
The rotation rate of the man is:
The resultant rotation rate of the system is computed from the Principle of Angular Momentum Conservation:
![(90\,kg)\cdot (5\,m)^{2}\cdot (0.16\,\frac{rad}{s} ) = [(90\,kg)\cdot (5\,m)^{2}+20000\,kg\cdot m^{2}]\cdot \omega](https://tex.z-dn.net/?f=%2890%5C%2Ckg%29%5Ccdot%20%285%5C%2Cm%29%5E%7B2%7D%5Ccdot%20%280.16%5C%2C%5Cfrac%7Brad%7D%7Bs%7D%20%29%20%3D%20%5B%2890%5C%2Ckg%29%5Ccdot%20%285%5C%2Cm%29%5E%7B2%7D%2B20000%5C%2Ckg%5Ccdot%20m%5E%7B2%7D%5D%5Ccdot%20%5Comega)
The final angular speed is:
Answer:
Acceleration = 9.8 m/sec2
Explanation:
We know that the acceleration due to gravity is 9.8 m/sec2 near the surface of earth.
Remember that the gravity is always affecting everything on earth at every instant, even the rock at the very top of it's trajectory. It doesn't mind if the velocity is zero for an instant or if there's air resistance, the gravity force is there, and always aims towards the center of the earth.
So for all the trajectory of the rock, gravity is 9.8 m/sec2
We can calculate the width/thickness of a coin using a screw gauge by placing it in between the teeth of the gauge.
<h3>How we can calculate the thickness using screw gauge?</h3>
We can determine the width/thickness of a coin by using a screw gauge because screw gauge is an instrument that measures thickness of an object that are very thin. First we can placed the coin in between the teeth of the gauge and then move the gauge until the coin can be held tightly. After that note the reading on the scale.
So we can conclude that we can calculate the width/thickness of a coin using a screw gauge by placing it in between the teeth of the gauge.
Learn more about thickness here: brainly.com/question/4937019
#SPJ1
Well, the spring constant is measured using the F=k∆x, where F is the force, k is the constant, and ∆x is the change in position. So if the mass is 1.98, the force (mxg) is 19.4. Thus the spring constant is 19.4/.0478(change in position). This equals 405.86.
