List of the metals that form only one type of ion (that is, metals whose charge is invariant from one compound to another) is below,
Here , we have to list the metals that form only one type of ion (that is, metals whose charge is invariant from one compound to another) and have to identify the group numbers of these metals.
- Hydrogen H+
- Lithium Li+
- Sodium Na+
- Potassium K+
- Rubidium Rb+
- Cesium Cs+
- Beryllium Be2+
- Magnesium Mg2+
- Calcium Ca2+
- Strontium Sr2+
- Barium Ba2+
- Aluminum Al3+
- Zinc Zn2+
- Scandium Sc3+
- Silver Ag+
Co is stable in both +2 and +3 oxidation state. So it can variable. Li only have +1 charge. So it is invariable from one compound to other.
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Answer:
Metallic bonds
Explanation:
Metallic bonds joins atoms of metals and atoms of alloys together. The copper used in making pennies is a metallic substance so it contains metallic bonds.
- The formation of this bond type is predicated on the large atomic radius, low ionization energy and large number of electrons in the valence shell.
- The bond is an attraction between the positive nuclei of all closely packed atoms in the lattice and the electron cloud.
- The electron cloud is jointly formed by all the atoms by losing their outermost shell electrons.
This way the bond in pennies are metallic in nature.
Work for a irreversible reaction, in thermodynamics, is calculated by multiplying the external pressure with the change in volume. Therefore,
Work = P ( V2 - V1 )
Work = 1.02 (1.403 - 0.055)
Work = 1.375 L-atm
Hope this answers the question. Have a nice day.
Answer:
The equation shows balance.
Explanation:
You can easily count the number of elements on each side.
On the left side of the equation, you have 2 moles of Na and 2 moles of Cl.
On the right side of the equation, you also have 2 moles of Na and 2 moles of Cl because the two elements formed a compound meaning that whatever number is in front of them, both elements will receive the same number.
Based on Le Chatelier's principle, the following factors will affect the chemical equilibrium
1) Temperature
2) Pressure
3) concentration
4) catalyst
The given equilibrium involves
H2(g) + I2(g) → 2HI(g)
The reactants are H2 and I2 while the product is HI. The equilibrium will be affected by changes in the concentration of H2, I2 or HI.
However, the equilibrium will not be affected by the addition of N2 since it is not involved in the reaction
Ans (c)
