Answer:
The molar mass of the vapor is 43.83 g/mol
Explanation:
Given volume of gas = V = 247.3 mL = 0.2473 L
Temperature = T = 100
= 373 K
Pressure of the gas = P = 745 mmHg (1 atm = 760 mmHg)
Mass of vapor = 0.347 g
Assuming molar mass of gas to be M g/mol
The ideal gas equation is shown below
The molar mass of the vapor comes out to be 43.834 g/mol
Answer:
Thermal energy always moves from where there is<u> more </u>of it to where there is<u> less </u>of it until <u>distributed</u>.
Explanation:
Its true, just don't know if its correct for your assignment
Answer:
2.7 g/cm³
Explanation:
Step 1: Calculate the mass of kerosene
The mass of the full beaker (mFB) is equal to the sum of the masses of the empty beaker (mEB) and the mass of the kerosene (mK).
mFB = mEB + mK
mK = mFB - mEB
mK = 60 g - 20 g = 40 g
Step 2: Calculate the density of kerosene
Density (ρ) is an intrinsic property of matter. It can be calculated as the quotient between the mass of kerosene and its volume.
ρ = m/V
ρ = 40 g/15 cm³ = 2.7 g/cm³
Because two different equations cannot have the same amount of heat being released unless they are equal and in this case they are not
