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kakasveta [241]
3 years ago
5

Which of the following elements has the ability to undergo sublimation

Chemistry
1 answer:
katovenus [111]3 years ago
6 0

Answer:

iodine

Explanation:

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10. Write the formula for the compounds: copper (1) chloride and copper (II) chloride
Natali [406]

Answer:

Copper(II) chloride (CuCl2) reacts with several metals to produce copper metal or copper(I) chloride (CuCl) with oxidation of the other metal.

Explanation:

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Rocks formed by changes in heat and pressure or the presence of hot
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The answer would be: Igneous Rocks

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What is the osmotic pressure, in atm, of a 0.287 M solution of MgCl2 at
Flauer [41]

Answer:

Π = 21.9 atm

Explanation:

The equation used to find osmotic pressure is:

Π = iMRT

In this formula,

   >> Π = osmotic pressure (atm)

   >> i = van't Hoff factor

   >> M = molarity (M)

   >> R = constant (0.0821 atm*L/mol*K)

   >> T = temperature (K)

Remember, van't Hoff factor is the amount of ions the species (MgCl₂) dissociates into while in solution. MgCl₂ dissociates into 3 ions. These ions are Mg²⁺ and 2 Cl⁻.

The temperature needs to be in Kelvin....

37.0 °C + 273.15 = 310.15 K

You now know the value of all the variables.

Π = iMRT

Π = (3)(0.287 M)(0.0821 atm*L/mol*K)(310.15 K)

Π = 21.9 atm

3 0
2 years ago
An element's _____ is its row in the periodic table
Dmitry_Shevchenko [17]
The answer is family
6 0
4 years ago
Read 2 more answers
What is the final volume of a 400.0 mL gas sample that is subjected to a
mestny [16]

Answer: 0.27L

Explanation:

Given that,

Original volume V1 = 400.0 mL

convert volume in milliliters to liters

(If 1000mL = 1L

400.0 mL = 400.0/1000 = 0.4 L)

Original temperature T1 = 22.0 °C

Convert temperature in Celsius to Kelvin

(22.0 °C + 273 = 295K)

Original pressure = 1000mmHg

Convert pressure of 1000mmHg to atm

(If 760mmHg = 1 atm

1000mmHg = 1000/760 = 1.316 atm)

New volume V2 = ?

New Temperature T2 = 30.0°C

(30.0°C + 273 = 303K)

New pressure P2 = 2 atm

Since pressure, volume and temperature are involved, apply the general gas equation

(P1V1)T1 = (P2V2)/T2

(1.316 atm x 0.4 L) /295K = (2 atm x V2) /303K

0.526 atmL / 295K = 2V2 / 303K

Cross multiply

0.526 atmL x 303K = 2V2 x 295K

159.47 = 590V2

Divide both sides by 590

159.47/590 = 590V2/590

0.27 L = V2

Thus, the final volume of the gas is 0.27L

7 0
3 years ago
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