Always remember that a compound can be separated into simpler substances by chemical methods/reactions. While elements cannot be broken down into simpler substances by chemical reactions. You can do a flame test and spectrum analysis to determine whether a solid material is an element or a compound. Check the boiling and/or melting point, color or density. Also check the solid material’s reaction with oxygen, hydrogen, calcium, or various acids. Examine and study its physical chemistry. The element(s) that may be present may be identified by checking the absorption edges from an x-ray spectrum.
For instance, a solid white material (A) is heated in the absence of air, decomposing to form a new white material (B) and gas (C). Gas (C) has the same properties as the products when carbon is burned in an excess of oxygen (CO2). How can we determine whether A, B, and C are elements or compounds? A would be a compound since it was broken down into B and C. So how do we determine B and C?
A compound can be decomposed, for the reason that a compound is composed of 2 or more elements. On the contrary, an element cannot be decomposed.
C6H15, C2H5 has a molar mass of 29g/mol. 87 divided by 29 is 3. Then multiply each element subscript by 3
Explanation:
It is known that equation for ideal gas is as follows.
PV = nRT
The given data is as follows.
Pressure, P = 1500 psia, Temperature, T =
= 104 + 460 = 564 R
Volume, V = 2.4 cubic ft, R = 10.73 
Also, we know that number of moles is equal to mass divided by molar mass of the gas.
n = 
m = 
=
= 9.54 lb
Hence, molecular weight of the gas is 9.54 lb.
- We will calculate the density as follows.
d = 
=
= 3.975 
- Now, calculate the specific gravity of the gas as follows.
Specific gravity relative to air =
= 
= 51.96
e kajajdjae no squo viboes we eso doadks Answer:ipao han meExplanation:no