Answer:
Explanation:
The formula for hydrogen atomic spectrum is as follows
energy of photon due to transition from higher orbit n₂ to n₁
For layman series n₁ = 1 and n₂ = 2 , 3 , 4 , ... etc
energy of first line
10.2 eV
wavelength of photon = 12375 / 10.2 = 1213.2 A
energy of 2 nd line
= 12.08 eV
wavelength of photon = 12375 / 12.08 = 1024.4 A
energy of third line
12.75 e V
wavelength of photon = 12375 / 12.75 = 970.6 A
energy of fourth line
= 13.056 eV
wavelength of photon = 12375 / 13.05 = 948.3 A
energy of fifth line
13.22 eV
wavelength of photon = 12375 / 13.22 = 936.1 A
Answer:
The man moves across the ice with a speed of 0.345m/s.
Explanation:
From the conservation of linear momentum, we have that the total linear momentum before the book throw is equal to the total linear momentum just after it. Since the initial velocity of the system is zero (so the initial momentum is zero), we have that:
Where 
is the mass of the man, 
is the mass of the book, and 
and 
are their velocities. Plugging in the given values, we can compute the speed of the man (ignoring the negative sign, because we care about the magnitude, not the direction):
In words, the resulting speed of the man is 0.345m/s.
Answer:
The initial speed of the cork was 1.57 m/s.
Explanation:
Hi there!
The equation of the horizontal position of the cork in function of time is the following:
x = x0 + v0 · t · cos θ
Where:
x = horizontal position at time t.
x0 = initial horizontal position.
v0 = initial speed of the cork.
t = time.
θ = launching angle.
If we place the origin of the frame of reference at the launching point, then x0 = 0.
We know that at t = 1.25 s, x = 1.50 m. We also know the launching angle so we can solve the equation of horizontal position for the initial speed, v0:
x = v0 · t · cos θ
x / t · cos θ = v0
v0 = 1.50 m / (1.25 s · cos (40.0°)
v0 = 1.57 m/s
The initial speed of the cork was 1.57 m/s.
Taking the vertical component of the displacement
1.1 - 0.2 = 0.9 mile
The horizontal component of the displacement
-0.3 mile
The magnitude of the displacement is
√[ (0.9)² + (-0.3) ] = 0.95 mile
The direction is
θ = tan-1 (-0.3/0.9)
θ = 161.57 degrees.
Answer:
179.47m/s
Explanation:
Using the law of conservation of momentum
m1u1 + m2u2 = (m1+m2)v
m1 and m2 are the masses
u1 and u2 are the initial velocities
v is the final velocity
Substitute
7750(179)+72(230) = (7750+72)v
1,387,250+16560 = 7822v
1,403,810 = 7822v
v = 1,403,810/7822
v= 179.47m/s
Hence the final velocity of the probe is 179.47m/s
