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Bas_tet [7]
3 years ago
12

On a container of chicken broth you notice the instructions to ""shake well before serving."" Which of the following best descri

bes the chicken broth? A. A solution B. An element C. A compound D. A suspension E. A pure substance
Chemistry
1 answer:
prohojiy [21]3 years ago
5 0

Answer:

The correct option is: D. A suspension

Explanation:

A suspension is a type of heterogeneous mixture in which solid particles are suspended through out the bulk of the solvent through mechanical agitation. The solid phase is also known as the internal phase and the solvent is known as external phase. In a suspension, the solid particles are generally larger than one micrometer and thus are unable to dissolve in the medium. The solid particles of a suspension are large enough to get precipitated.

<u>Therefore, in the given situation, the chicken broth is </u><u>a suspension</u><u> </u>as the contents or solid particles of the container needs to be suspended in the solvent by shaking to prevent sedimentation.

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Why does a solution of acid and sodium thiosulfate go cloudy
klemol [59]
The soulustion. turn cloudy due to the precipitation of Sulphur.
4 0
3 years ago
What is the importance of standardization in chemistry​
Anika [276]

Answer:

Standardisation is used to determine the concentration of a volumetric solution in order to achieve accurate and reliable titration results

5 0
4 years ago
g Ammonia has been studied as an alternative "clean" fuel for internal combustion engines, since its reaction with oxygen produc
Gala2k [10]

\text{Ammonia has been studied as an alternative "clean" fuel for internal combustion}

\text{engines, since its reaction with oxygen produces only nitrogen and water vapor,}

\text{and in the liquid form it is easily transported. An industrial chemist studying this}

\text{reaction fills a} \ \mathbf{100 \  L }\ \text{tank with} \ \mathbf{8.6 \ mol} \ \text{of ammonia gas and} \ \mathbf{28 \ mol} \ \  \text{of oxygen gas, }

\text{to be} \  \mathbf{2.6\  mol} \ .\ \text{Calculate the concentration equilibrium constant for the combustion of}

\text{ammonia at the final temperature of the mixture. Round your answer to  2 significant digits.}

Answer:

Explanation:

From the correct question above:

The reaction can be represented as:

\mathbf{4 NH_3_{(g)}+ 3O_{2(g)} \iff 2N_{2(g)}+ 6H_2O_{(g)} }

From the above reaction; the ICE table can be represented as:

                    \mathbf{4 NH_3_{(g)}+ 3O_{2(g)} \iff 2N_{2(g)}+ 6H_2O_{(g)} }

I (mol/L)     0.086            0.28                 0              0

C                   -4x                -3x               +2x           +6x

E                 0.086 - 4x     0.28 - 3x      +2x             +6x

At equilibrium;

The water vapor = \dfrac{2.6 \ mol}{100 \ L} = 6x

x = \dfrac{2.6}{100} \times \dfrac{1}{6}

x = 0.00433

\text{equilibrium constant}  ({k_c}) =  \dfrac{ [N_2]^2 [H_2O]^6 }{ [[NH_3]^4] [O_2]^3 }

\implies \dfrac{(2x)^2 (6x)^6}{(0.086-4x)^4\times (0.28-3x)^3} \\ \\

Replacing the value of x, we have:

K_c = \dfrac{4 \times 46,656 \times x^8}{(0.086-4x)^4\times (0.28 -3x)^3} \\ \\ K_c = \dfrac{4 \times 46656 \times (0.00433)^8}{(0.06868)^4(0.26701)^3} \\ \\ K_c = \mathbf{5.4446 \times 10^{-8}}

K_c = \mathbf{5.5 \times 10^{-8} \ to  \ 2 \ significant \ figures}

5 0
3 years ago
Determine the oxidation number of each element in these compounds or ions. (a) au2(seo4)3 (gold(iii) selenate) au = se = o = (b)
Stels [109]
<span>                                                    Au</span>₂(SeO₄)₃

                                         O = -2 × 4 = -8
                                             Se  =  + 6
So,
                                            (+6 - 8) = -2

Means (SeO₄) contains -2 charge, Now multiply -2 by 3
                                             
                                             -2 ₓ 3 = -6
Means,
                             Au₂ + (-6) = 0
               
                            Au₂  = +6
Or,
                            Au  =  6 / 2

                            Au  = +3
Result:
                            Au  =  +3
                            Se  =  +6
                            O   =  -2

                                                      Ni(CN)₂


Cyanide (CN⁻) contains -1 charge,
So,
                              N  =  -3
                              C  =  +2
Then,
                                         Ni + (-1)₂  =  0

                                               Ni - 2  =  0
Or,
                                                     Ni =  +2
Result:
                            N  =  -3
                            C  =  +2
                           Ni  =  +2




6 0
4 years ago
Which of the following compounds would be primarily ionic? Methane CH4 , Ammonia NH3, Calcium Chloride CaCL2 or Carbon dioxide,
vagabundo [1.1K]
Definitely Calcium Chloride.
All the others are covalent.
7 0
3 years ago
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