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Bas_tet [7]
3 years ago
12

On a container of chicken broth you notice the instructions to ""shake well before serving."" Which of the following best descri

bes the chicken broth? A. A solution B. An element C. A compound D. A suspension E. A pure substance
Chemistry
1 answer:
prohojiy [21]3 years ago
5 0

Answer:

The correct option is: D. A suspension

Explanation:

A suspension is a type of heterogeneous mixture in which solid particles are suspended through out the bulk of the solvent through mechanical agitation. The solid phase is also known as the internal phase and the solvent is known as external phase. In a suspension, the solid particles are generally larger than one micrometer and thus are unable to dissolve in the medium. The solid particles of a suspension are large enough to get precipitated.

<u>Therefore, in the given situation, the chicken broth is </u><u>a suspension</u><u> </u>as the contents or solid particles of the container needs to be suspended in the solvent by shaking to prevent sedimentation.

You might be interested in
Which statement below correctly describes the relationship between Q and K for both reactions? Are these reactions spontaneous a
nikklg [1K]

Answer:

Q < K for both reactions. Both are spontaneous at those concentrations of substrate and product.

Explanation:

Hello,

In this case, the undergoing chemical reactions with their proper Gibbs free energy of reaction are:

A->B;\Delta _rG^o=-13 kJ/mol

C ->D ;\Delta _rG^o=3.5 kJ/mol

The cellular concentrations are as follows: [A] = 0.050 mM, [B] = 4.0 mM, [C] = 0.060 mM and [D] = 0.010 mM.

For each case, the reaction quotient is:

Q_1=\frac{4.0mM}{0.050mM}=80\\ Q_2=\frac{0.010mM}{0.060mM}=0.167

A typical temperature at a cell is about 30°C, in such a way, the equilibrium constants are:

K_1=exp(-\frac{-13000J/mol}{8.314J/mol*K*303.15K} )=173.8\\K_2=exp(-\frac{3500J/mol}{8.314J/mol*K*303.15K} )=0.249

Therefore, Q < K for both reactions. Both are spontaneous at those concentrations of substrate and product.

Best regards.

6 0
3 years ago
At equilibrium, the concentrations in this system were found to be [N2]=[O2]=0.200 M and [NO]=0.400 M.
Kipish [7]

Answer:

The concentration in equilibrium of NO is 0,550M.

Explanation:

For the reaction:

N₂(g) + O₂(g) ⇄ 2NO

The equilibrium constant is defined as:

k = [NO]² / [N₂][O₂] <em>(1)</em>

Replacing for the concentrations in equilibrium:

k = (0,400M)² / (0,200M)(0,200M)

<em>k = 4,000</em>

If you add more NO until 0,700M, the equilibrium concentrations will be:

[NO] = 0,700M-2x

[N₂] = 0,200M+x

[O₂] = 0,200M+x

Replacing in (1)

4,000 =  (0,700M-2x)² / (0,200M+x)²

4,000 =  4x²- 2,8x + 0,49 / x² + 0,4x + 0,04

4x² + 1,6x + 0,16 = 4x²- 2,8x + 0,49

4,4x = 0,33

x = 0,075M

That means that concentration in equilibrium of NO is:

[NO] = 0,700M - 2×0,075M = <em>0,550M</em>

I hope it helps!

4 0
3 years ago
An aqueous solution contains 0.397 M ammonia. Calculate the pH of the solution after the addition of 4.63 x 10-2 moles of perchl
SSSSS [86.1K]

Answer:

9.308

Explanation:

The computation of the pH of the given solution is shown below:

But before we need to determine the HI molarity which is

Molarity\ of\ HI = \frac{moles}{volume \ in\ L}

= \frac{4.63\times10^{-2}}{0.250}

= 0.1852  M

Now

As we know that

NH_3 + HI = NH_4I

So,

NH_4I = HI = 0.1852 M

Now the molarity of NH_3 left is

= 0.397 - 0.1852

= 0.2118

pOH = pKb + log (\frac{NH_4I}{NH_3})

= 4.75 + log(\frac{0.1852}{0.2118})

= 4.692

Now as we know that

pH = 14 - pOH

= 14 - pOH

= 14 - 4.692

= 9.308

We simply applied the above equations

5 0
3 years ago
If a pea plant is tall, and tallness in pea plants is dominant over shortness, what is the phenotype of the pea plant?
Firlakuza [10]

Answer:

The height of the plant is controlled by two alleles - the dominant 'T' for tallness and recessive 't' for shortness of the plant. The dominant allele represses the expression of the recessive allele. The recessive allele is expressed only in the homozygous state (tt)

6 0
2 years ago
Read 2 more answers
List the following elements in order from lowest boiling point to highest
-BARSIC- [3]

Answer:

Aluminum lodide - 680 degrees

fructose- 824 degrees

potassium bromide- 2,615 degrees

calcium bromide 3, 515 degrees

lowest boiling point is 680 and highest is 3,515.

hope this helps:)

7 0
2 years ago
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