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garri49 [273]
4 years ago
15

An element has three naturally occurring isotopes. ten percent (.10) occurs as 55^x, fifteen percent (.15) occurs as isotope 56^

x, and seventy-five percent (.75) occurs as 57^x. calculate the weighted atomic mass of element x to the nearest tenth
Chemistry
1 answer:
Leviafan [203]4 years ago
5 0
The average atomic weight is, from the name itself, the average weight of all its naturally occurring isotopes. All you have to do is multiple the abundance of each isotope with its individual mass, then add them altogether.

Mass = (0.10*55)+(0.15*56)+(.75*57)
<em>Mass = 56.65 amu</em>
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The correct answer is : No, because there are 4 hydrogen atoms on the reactants side and 2 on the products side.

Explanation:

NH_4NO_3\rightarrow N_2O+H_2O

The given reaction equation is not balanced because:

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<u>Answer:</u> The moles of water produced are 1.54 moles.

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\text{Moles of ethane}=\frac{15.42g}{30.07g/mol}=0.513mol

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By Stoichiometry of the reaction:

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