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irina [24]
3 years ago
6

A point in the figure is selected at random. Find the probability that the point will be in the part that is NOT shaded.

Mathematics
1 answer:
creativ13 [48]3 years ago
3 0

Answer:

About 20%

Step-by-step explanation:

The probability of a point on the un-shaded region will be given by;

Area of the shaded region/total area

Considering that the circles are of the same size, then the length of the square is 2d

Area of the square = 4d²

Area of the shaded = (4d² -4π(d/2)²

                                = 4d² -πd², but π = 22/7

                                = 6/7d²

Probability = (6/7d² ÷ 4d²) × 100%

                  = (6/28 d²) × 100%

                  = 21.42 %

Therefore; the answer is about 20%

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Give the slope of the graph and the unit rate
Lerok [7]

Answer:

y=5/4 x

The slope is 5/4

Step-by-step explanation:

To solve this problem we need  to find the equation of the line, y=mx+b

We've been given a table with several points, so we can use two of them to perform our calculus.

To obtain the slope we need to use the equation of slopes:

m=\frac{y_{2}-y_{1}}{x_{2}-x_{1}}

Where (x1,y1) =(4,5) and (x2,y2)=(8,10)

m= (10-5)/(8-4)=5/4

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10=5/4 *8 +b

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6 0
3 years ago
A line is defined by the equation y = negative x + 3. Which shows the graph of this line?
never [62]

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Its the First Graph

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3 0
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Read 2 more answers
The half-life of radium-226 is 1600 years. Suppose we have a 27-mg sample.
slega [8]

A function m(t)= m₀e^(-rt) that models the mass remaining after t years is; m(t) = 27e^(-0.00043t)

The amount of sample that will remain after 4000 years is; 4.8357 mg

The number of years that it will take for only 17 mg of the sample to remain is;  1076 years

<h3>How to solve exponential decay function?</h3>

A) Using the model for radioactive decay;

m(t)= m₀e^(-rt)

where;

m₀ is initial mass

r is rate of growth

t is time

Thus, we are given;

m₀ = 27 mg

r = (In 2)/1600 = -0.00043 which shows a decrease by 0.00043

and so we have;

m(t) = 27e^(-0.00043t)

c) The amount that will remain after 4000 years is;

m(4000) = 27e^(-0.00043 * 4000)

m(4000) = 27 * 0.1791

m(4000) = 4.8357 mg

d) For 17 mg to remain;

17 = 27e^(-0.00043 * t)

17/27 = e^(-0.00043 * t)

In(17/27) = -0.00043 * t

-0.4626/-0.00043 = t

t = 1076 years

Read more about Exponential decay function at; brainly.com/question/27822382

#SPJ1

5 0
1 year ago
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