The compound that would be most reactive is Ethyne (answer A)
<u><em> explanation</em></u>
- Ethyne is the most unsaturated among the four compounds ( <em> it has a triple bond between the two carbon atoms) .</em>
- The triple bond in ethyne is made up of 1 sigma bond and 2π bond.
- <em>The 2π bond are weaker and can easily break which make Ethyne more reactive than Ethene, methane and Ethane.</em>
Answer: The answers are:
The number of protons in an atom of an element is unique to each element.
A proton in an atom of one element is identical to a proton in an atom of another element.
Explanation: The number of protons in an atom of an element is unique to each element. The number of protons in an atom of an element is the atomic number of that element. Atomic number determines the chemical properties and reactivity of the atom.
All atoms are made up of three particles: protons, electrons and neutrons. These particles are identical in all the elements, what distinguishes one element from another is the number of each of these particles it contains. Therefore, a proton in an atom of one element is identical to a proton in an atom of another element likewise the electrons and neutrons.
Answer:
It partially ionizes
Explanation:
Higher tier) Weak acids only partially ionise in water. Only a small fraction of their molecules break into hydrogen ions when added to water.
Answer:
The Mouse population will increase: True
The Grass population will increase: False
The Hawk Population will increase: False
The Mouse population will decrease: False
Explanation: This is true because now there is no snake to kill them off. Still, there is the hawk that is there but there will be a general increase in the mouse population
Answer:
Explanation:
Gases are:
Gas 1 = X
Gas 2 = Y
To calculate the rates of effusion we apply the Graham's Law of Diffusion of Gases.
The law relates the rate of diffusion or effusion of a gas to the type of molecule in the gas.
It is expressed as "the rate of diffusion or effusion of a gas is inversely proportional to the square root of its molecular mass or density at constant temperature and pressure".
A gas with low molecular mass can diffuse or effuse more rapidly than one with high molecular mass under similar conditions.
By this, we can express a mathematical relationship to solve for the molecular masses of the gases.
![\frac{r_{x} }{r_{y} } = \frac{\sqrt{m_{y} } }{\sqrt{m_{x} } }](https://tex.z-dn.net/?f=%5Cfrac%7Br_%7Bx%7D%20%7D%7Br_%7By%7D%20%7D%20%3D%20%5Cfrac%7B%5Csqrt%7Bm_%7By%7D%20%7D%20%7D%7B%5Csqrt%7Bm_%7Bx%7D%20%7D%20%20%7D)
r is the rate of diffusion
m is the molecular mass