Question

Chegg an insulated rigid tank contains 12 kg of air at 200 kpa and 500 c. The tank valve is opened, and pressure reduces to 75 kpa through an isentropic process. Determine the final temperature (k)

Answer 1

In thermodynamics, the adiabatic and reversible system is the isotropic process. The final temperature of the system is 311.08 degrees celsius.

What are isotropic conditions?

Isotropic conditions are the process of the thermodynamic system that has no net transfer of heat.

Given,

Initial temperature = 773.15 Kelvin

Initial pressure = 200

Final pressure = 75

The final temperature is calculated as:

$\rm \dfrac{T_{2}}{T_{1}} = \rm \dfrac{P_{2}}{P_{1}} ^{y- \frac{1}{y}}$

Substituting values:

$\begin{aligned}\rm \dfrac{T_{2}}{773} &= \dfrac{75}{200}^{1.4- \frac{1}{1.4}}\\\\&= 584.08 \;\rm kelvin\end{aligned}$

Therefore, 584.08 K or 311.08 degrees celsius is the final temperature.

Learn more about the isotropic system here:

brainly.com/question/13497738

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