Drop out my dude whatever this is ain’t worth it
Answer:
677.76 g of oxygen needed.
Explanation:
Given data:
Mass of glucose = 635.2 g
Mass of oxygen needed = ?
Solution:
Chemical equation:
C₆H₁₂O₆ + 6O₂ → 6CO₂ + 6H₂O + energy
Number of moles of glucose:
Number of moles = mass/ molar mass
Number of moles = 635.2 g / 180.156 g/mol
Number of moles = 3.53 mol
Now we will compare the moles of glucose with oxygen.
C₆H₁₂O₆ : O₂
1 : 6
3.53 : 6×3.53 = 21.18 mol
Mass of oxygen:
Mass = number of moles × molar mass
Mass = 21.18 g × 32 g/mol
Mass = 677.76 g
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Answer:
CO is considered as a product.
Explanation:
A general chemical equation for a combination reaction follows:
To write a chemical equation, we must follow some of the rules:
The reactants must be written on the left side of the direction arrow.
A '+' sign is written between the reactants, when more than one reactants are present.
An arrow is added after all the reactants are written in the direction where reaction is taking place. Here, the reaction is taking place in forward direction.
The products must be written on the right side of the direction arrow.
A '+' sign is written between the products, when more than one products are present.
For the given chemical equation:
are the reactants in the reaction and are the products in the reaction.
Hence, CO is considered as a product.
Answer:
Explanation:
Have the class stand up. Tell them that they will be flipping the penny (you will tell them when); each time they flip one half life will have passed. If their penny lands on heads, they are radioactive and have decayed and they should sit; if their penny lands on tails, they have not decayed and may remain standing.
