Question

1. On each of your equipotential maps, draw some electric field lines with arrow heads indicating the direction of the field. (Hint: At what angle do field lines intersect equipotential lines?) Draw sufficient field lines that you can "see" the electric field.

Answer 1

Answer:

The angle between the electric field lines and the equipotential surface is 90 degree.

Explanation:

The equipotential surfaces are the surface on which the electric potential is same. The work done in moving a charge from one point to another on an equipotential surface is always zero.

The electric field lines are always perpendicular to the equipotential surface.

As

$dV = \overrightarrow{E} . d\overrightarrow{r}$

For equipotential surface, dV = 0 so

$0 = \overrightarrow{E} . d\overrightarrow{r}$

The dot product of two non zero vectors is zero, if they are perpendicular to each other.