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2 years ago

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1. On each of your equipotential maps, draw some electric field lines with arrow heads indicating the direction of the field. (H

int: At what angle do field lines intersect equipotential lines?) Draw sufficient field lines that you can "see" the electric field.

1 answer:

JulijaS [17]2 years ago

5 0

Answer:

The angle between the electric field lines and the equipotential surface is 90 degree.

Explanation:

The equipotential surfaces are the surface on which the electric potential is same. The work done in moving a charge from one point to another on an equipotential surface is always zero.

The electric field lines are always perpendicular to the equipotential surface.

As

$dV = \overrightarrow{E} . d\overrightarrow{r}\\\\$

For equipotential surface, dV = 0 so

$0 = \overrightarrow{E} . d\overrightarrow{r}\\\\$

The dot product of two non zero vectors is zero, if they are perpendicular to each other.

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A 1.00 kg particle has the xy coordinates (-1.20 m, 0.500 m) and a 4.50 kg particle has the xy coordinates (0.600 m, -0.750 m).

just olya [345]

Answer:

a) The x coordinate of the third mass is -1.562 meters.

b) The y coordinate of the third mass is -0.944 meters.

Explanation:

The center of mass of a system of particles ( $\vec r_{cm}$ ), measured in meters, is defined by this weighted average:

$\vec r_{cm} = \frac{\Sigma_{i=1}^{n}\,m_{i}\cdot \vec r_{i}}{\Sigma_{i=1}^{n}\,m_{i}}$ (1)

Where:

$m_{i}$ - Mass of the i-th particle, measured in kilograms.

$\vec r_{i}$ - Location of the i-th particle with respect to origin, measured in meters.

If we know that $\vec r_{cm} = (-0.500\,m,-0.700\,m)$ , $m_{1} = 1\,kg$ , $\vec r_{1} = (-1.20\,m, 0.500\,m)$ , $m_{2} = 4.50\,kg$ , $\vec r_{2} = (0.600\,m, -0.750\,m)$ and $m_{3} = 4\,kg$ , then the coordinates of the third particle are:

$(-0.500\,m, -0.700\,m) = \frac{(1\,kg)\cdot (-1.20\,m,0.500\,m)+(4.50\,kg)\cdot (0.600\,m,-0.750\,m)+(4\,kg)\cdot \vec r_{3}}{1\,kg+4.50\,kg+4\,kg}$

$(-4.75\,kg\cdot m, -6.65\,kg\cdot m) = (-1.20\,kg\cdot m, 0.500\,kg\cdot m) + (2.7\,kg\cdot m, -3.375\,kg\cdot m) +(4\cdot x_{3},4\cdot y_{3})$

$(4\cdot x_{3}, 4\cdot y_{3}) = (-6.25\,kg\cdot m,-3.775\,kg\cdot m)$

$(x_{3},y_{3}) = (-1.562\,m,-0.944\,m)$

a) The x coordinate of the third mass is -1.562 meters.

b) The y coordinate of the third mass is -0.944 meters.

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2 years ago

Define discrimination and write a sentence using the word.

seraphim [82]

Answer:

discrimination: prejudice towards a person/group based on their race, sex, age, and/or sexual orientation

Explanation:

People of color face discrimination because of the color of their skin.

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2 years ago

Read 2 more answers

How are astronomers able to observe and study black holes?

Ber [7]

Although scientists can't detect or observe black holes with telescopes that detect x-rays, light, or other many other different forms of electromagnetic radiation and waves. But they can detect and study them by the effect of matter near it. If a black hole passes through a cloud of interstellar matter, it will draw matter inward (this process is known as accretion). A similar process occurs when a star passes through a black hole. When this happens, a star can break apart as it pulls it self toward it. As the attracted matter accelerates and starts heating up, it emits x-rays that are radiate into space.
Recent studies do show that black do have a very big influence towards neighborhoods around it. The black hole emits gamma ray bursts, devouring nearby stars, and spurring the growth of new stars in some areas while stalling it in others.

Info: https://science.nasa.gov/astrophysics/focus-areas/black-holes

Hope this Helps! (:

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2 years ago

What is the amount of work done when JoAnne throws a baseball 2 meters at a force of 40

sergiy2304 [10]

Answer:

Amount of work done by Joanne = 80 joule

Explanation:

Given:

Displacement of ball = 2 meters

Force applied = 40 newtons

Find:

Amount of work done by Joanne

Computation;

Work done = Force applied x Displacement

Amount of work done by Joanne = Force applied x Displacement of ball

Amount of work done by Joanne = 40 x 2

Amount of work done by Joanne = 80 joule

5 0

2 years ago

A 4.0-kg falcon catches a 1.0-kg dove from behind in midair. What is their velocity after impact if the falcon’s velocity is ini

Grace [21]

Answer:

V = 2.8 m/s

Explanation:

It is given that,

Mass of falcon, $m_1=4\ kg$

Mass of dove, $m_2=1\ kg$

Initial velocity of falcon, $u_1=3\ m/s$

Initial velocity of dove, $u_2=2\ m/s$

When the falcon catches the dove, the momentum remains conserved. Using the formula for the conservation of momentum as :

$m_1u_1+m_2u_2=(m_1+m_2)V$

V is the velocity after impact

$V=\dfrac{m_1u_1+m_2u_2}{(m_1+m_2)}$

$V=\dfrac{4\times 3+1\times 2}{(4+1)}$

V = 2.8 m/s

So, their velocity after the impact is 2.8 m/s. Hence, this is the required solution.

7 0

3 years ago