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3 years ago

What are the subzones for each main zone?

Physics

1 answer:

Makovka662 [10]3 years ago

5 0

Answer:

The oceanic zone is subdivided into the epipelagic, mesopelagic, and bathypelagic zones on the basis of amount of light that reaches different depths. The mesopelagic (disphotic) zone, where only small amounts of light penetrate, lies below the Epipelagic zone.

Explanation:

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A bullet is fired at an angle θ above the horizontal with an initial velocity of 800 m/s from the top of an 80 m high tower. Wha

Irina-Kira [14]

Answer:

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6 0

2 years ago

an empty density bottle weighed 23.5 and 48.4g when filled with water .The empty bottle was partially filled with sand until and

gavmur [86]

Answer:

Density of Sand is $2.653g/cm^{3}$ .

Explanation:

Given Empty Density bottle weighs 23.5gm(W=23.5gm)

Weight of bottle when completely filled water=48.4gm

So amount of water required to fill the bottle=Weight of bottle filled with water-W

Amount of water required to fill the bottle( $w_{max}$ )=48.4gm-23.5gm

$w_{max}=24.9$ g

Since we know density of water $d_{w} =1g/cm^{3}$ and $w_{max}$

We can calculate volume of empty space in the bottle(V).

$w_{max}=d_{w}$ $\times$ V

V= $\frac{w_{max} }{d_{w} }$

V= $\frac{24.9}{1}$

V=24.9 $g/cm^{3}$

Now bottle is partially filled with sand,and weight of bottle is ( $w_{s}$ )36.5gm

So,

Amount of sand added ( $m_{s}$ )=36.5-Weight of the bottle

$m_{s}$ =13g

After filling the bottle with water again,the weight of the bottle becomes ( $W_{2}$ =56.5g)

Therefore,

amount of water added to the bottle of sand in grams = $W_{2}$ -36.5gm

amount of water added =56.5g-36.5g

amount of water added =20g

As the density of water = 1g/ $cm^{3}$

Amount of water (in grams )=Volume of water occupied

20=volume of water added

Therfore volume of water added to the sand filled bottle( $V_{w}$ )=20 $cm^{3}$

As we know the total volume of the water bottle(V),

Volume of the sand occupied in the water bottle=V- $V_{w}$

$V_{s}$ =24.9g-20g

$V_{s}$ =4.9g

We know,

Density=Mass/Volume

Therefore,

density of sand = $\frac{m_{s} }{V_{s} }$

density of sand = $\frac{13}{4.9}$

density of sand = $2.653g/cm^{3}$

8 0

3 years ago

There are 11 lights in series, and they are in series with 2 lights in parallel. If the 13 lights are identical, which of them w

BlackZzzverrR [31]

<h2>Answer: 2 lights (in parallel)</h2>

Explanation:

When light bulbs are connected in series the total voltage $V_{s}$ will be:

$V_{s}=V_{1}+V_{2}+...+V_{n}$ (1)

This means the <u>total voltage will be distributed among each of the bulbs</u> in series, therefore the luminosity will be also divided among the bulbs.

When lights are connected in parallel the total voltage $V_{p}$ will be:

$V_{p}=V_{1}=V_{2}=...=V_{n}$ (2)

This means the <u>total voltage will be the same for each bulbs</u> in parallel, therefore the luminosity will be the same.

Now, if we combine this two types of connections, as in this problem with 11 lights in series, which are also in series with 2 lights in parallel; the 2 lights in parallel will be brighter than the 11 lights in series.

8 0

3 years ago

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QveST [7]

The angle of reflection is 42 degrees because it says the angle of incidence is equal to the angle of reflection

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3 years ago

What Device can be used to increase voltage from a source of direct-current?

Rudiy27

Multi meter reading instruments Device can be used to increase voltage know direct-current

4 0

3 years ago