Answer:
-2.79 × 10³ cal
Explanation:
Step 1: Given data
- Mass of water (m): 35.0 g
- Latent heat of fusion of water (L): -79.7 cal/g
Step 2: Calculate the heat required to freeze 35.0 g of water
We have 35.0 g of liquid water and we want to freeze it, that is, to convert it in 35.0 g of ice (solid water), at 0 °C (melting point). We can calculate the heat (Q) that must be released using the following expression.
Q = L × m
Q = -79.7 cal/g × 35.0 g
Q = -2.79 × 10³ cal
Answer:
+3
Explanation:
If an atom loses electrons, it becomes positive. Because silver loses 3 electrons, the charge becomes positive 3.
Skeletal Equation
Ba(NO3)2 + KCl = BaCl2+ KNO3
Balanced equation
Ba(NO3)2 + 2KCl = BaCl2 + 2KNO3
On the earth there is the top layer dirt then loam comes next
