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The principle of cross-cutting relationships states that a fault or intrusion is younger than the rocks that it cuts. The fault labeled 'E' cuts through all three sedimentary rock layers (A, B, and C) and also cuts through the intrusion (D). So the fault must be the youngest formation that is seen.
<em>-</em><em> </em><em>BRAINLIEST</em><em> answerer</em>
Answer:
ω = √(2T / (mL))
Explanation:
(a) Draw a free body diagram of the mass. There are two tension forces, one pulling down and left, the other pulling down and right.
The x-components of the tension forces cancel each other out, so the net force is in the y direction:
∑F = -2T sin θ, where θ is the angle from the horizontal.
For small angles, sin θ ≈ tan θ.
∑F = -2T tan θ
∑F = -2T (Δy / L)
(b) For a spring, the restoring force is F = -kx, and the frequency is ω = √(k/m). (This is derived by solving a second order differential equation.)
In this case, k = 2T/L, so the frequency is:
ω = √((2T/L) / m)
ω = √(2T / (mL))
We have: K.E. = mv² / 2
here, m = 4 Kg
v = 9 m/s
Substitute their values into the expression:
K.E. = (4)(9)² / 2
K.E. = (4)(81) / 2
K.E. = 324 / 2
K.E. = 162 Joules
In short, Your Answer would be 162 J
Hope this helps!
Complete Question
The complete question is shown on the first uploaded image
Answer:
The uncertainty in inverse frequency is ![\Delta [\frac{1}{w} ]= \frac{3}{2000} \ s](https://tex.z-dn.net/?f=%5CDelta%20%20%5B%5Cfrac%7B1%7D%7Bw%7D%20%5D%3D%20%20%5Cfrac%7B3%7D%7B2000%7D%20%5C%20s)
Explanation:
From the question we are told that
The value of the proportionality constant is 
The strength of the magnetic field is 
The change in this strength of magnetic field is 
The magnetic field is given as
Where 
is frequency
The uncertainty or error of the field is given as
![\Delta B = \frac{k }{[\frac{1}{w}^]^2 } \Delta [\frac{1}{w} ]](https://tex.z-dn.net/?f=%5CDelta%20%20B%20%20%3D%20%20%5Cfrac%7Bk%20%7D%7B%5B%5Cfrac%7B1%7D%7Bw%7D%5E%5D%5E2%20%7D%20%20%5CDelta%20%5B%5Cfrac%7B1%7D%7Bw%7D%20%5D)
The uncertainty in inverse frequency is given as
![\Delta [\frac{1}{w} ] = \frac{\Delta B}{k [\frac{1}{w^2} ]}](https://tex.z-dn.net/?f=%5CDelta%20%20%5B%5Cfrac%7B1%7D%7Bw%7D%20%5D%20%20%3D%20%5Cfrac%7B%5CDelta%20B%7D%7Bk%20%5B%5Cfrac%7B1%7D%7Bw%5E2%7D%20%5D%7D)
![\Delta [\frac{1}{w} ]= \frac{\Delta B}{k (B)^2 }](https://tex.z-dn.net/?f=%5CDelta%20%20%5B%5Cfrac%7B1%7D%7Bw%7D%20%5D%3D%20%20%5Cfrac%7B%5CDelta%20B%7D%7Bk%20%28B%29%5E2%20%7D)
substituting values
![\Delta [\frac{1}{w} ]= \frac{3}{5 (20)^2 }](https://tex.z-dn.net/?f=%5CDelta%20%20%5B%5Cfrac%7B1%7D%7Bw%7D%20%5D%3D%20%20%5Cfrac%7B3%7D%7B5%20%2820%29%5E2%20%7D)
Id say both. all organisms perform cellular respiration, and plants perform photosynthesis, as well as cellular respiration.
