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san4es73 [151]
3 years ago
11

An electric fan has a low speed of 3.00 rotations per second and a medium speed of 9.00 rotations per second. The fan rotates co

unter-clockwise, CCW. a) The fan is running on low speed when it is switched to medium speed. It takes 4.00 seconds for the fan to reach medium speed. What is the angular acceleration, LaTeX: \alphaα? b) If the rotational inertia of the fan is Ifan = 1.50 x 10-3 kg-m2, calculate the Net torque, LaTeX: \tau_{net}τ n e t, required for part a.
Physics
1 answer:
Korolek [52]3 years ago
7 0

Answer:

α=9.42 rad/s    T= 0.014 rad/s^{2}

Explanation:

Low speed= Wi=3 rps = 3*2*π rad/s= 6π rad/sec

Medium speed= Wf= 9 rps= 9*2*π rad/sec= 18 rad/sec

time= t= 4 sec

Angular acceleration=α=\frac{Wf-Wi}{t}

⇒α=(18 π - 6 π)/4

⇒α=9.42 rad/s

b).

Rotational inertia= I = 1.5*10^-3 kg-m^2

Net torque= T = I*α = (1.5*10^-3) * (9.42) rad/s^2

⇒T= 0.014 rad/s^2

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How much power is needed to lift the 200-N object to a height of 4 m in 4 s?
Vitek1552 [10]

Answer: 2000 watts

Explanation:

Given that,

power = ?

Weight of object = 200-N

height = 4 m

Time = 4 s

Power is the rate of work done per unit time i.e Power is simply obtained by dividing work by time. Its unit is watts.

i.e Power = work / time

(since work = force x distance, and weight is the force acting on the object due to gravity)

Then, Power = (weight x distance) / time

Power = (200N x 4m) / 4s

Power = 8000Nm / 4s

Power = 2000 watts

Thus, 2000 watts of power is needed to lift the object.

3 0
3 years ago
A stunt driver rounds a banked, circular curve. The driver rounds the curve at a high, constant speed, such that the car is just
bagirrra123 [75]

Answer: C

Frictional force

Explanation:

The description of the question above is an example of a circular motion.

For a car travelling in a curved path, the frictional force between the tyres and the road surface will provide the centripetal force.

Since the road is banked, and the cross section of the banked road is constructed like a ramp. The car drives transversely to the slope of the ramp, so that the wheels of one side of the car are lower than the wheels on the other side of the car, for cornering the banked road, the car will not rely only on the frictional force.

Therefore, the correct answer is option C - the frictional force.

5 0
3 years ago
Please help (will mark brainliest)
serg [7]

Answer:

if im not mistaken i think its d let me know if correct plz

7 0
2 years ago
Read 2 more answers
Two equal charges with magnitude Q and Q experience a force of 12.3442 when held at a distance r. What is the force between two
Pepsi [2]

Answer:197.504 N

Explanation:

Given

Two Charges with magnitude Q experience a  force of 12.344 N

at distance r

and we know Electrostatic force is given

F=\frac{kq_1q_2}{r^2}

F=\frac{kQ\cdot Q}{r^2}

F=\frac{kQ^2}{r^2}

Now the magnitude of charge is 2Q and is at a distance of \frac{r}{2}

F'=\frac{k2Q\cdot 2Q}{\frac{r^2}{2^2}}

F'=16F

F'=197.504 N

4 0
3 years ago
An engine moves a motorboat through water at a constant velocity of 22 meters/second. If the force exerted by the motor on the b
trapecia [35]

Answer: Option B: 1.3×10⁵ W

Explanation:

Power = \frac{Work \hspace{1mm} done}{Time}

P=\frac{W}{t}

Work Done, W= F.s

Where s is displacement in the direction of force and F is force.

\Rightarrow P = \frac{F.s}{t} =F \times \frac{s}{t}=F.v

where, v is the velocity.

It is given that, F = 5.75 × 10³N

v = 22 m/s

P = 5.75 × 10³N×22 m/s = 126.5 × 10³ W ≈1.3×10⁵W

Thus, the correct option is B

6 0
3 years ago
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