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san4es73 [151]
3 years ago
11

An electric fan has a low speed of 3.00 rotations per second and a medium speed of 9.00 rotations per second. The fan rotates co

unter-clockwise, CCW. a) The fan is running on low speed when it is switched to medium speed. It takes 4.00 seconds for the fan to reach medium speed. What is the angular acceleration, LaTeX: \alphaα? b) If the rotational inertia of the fan is Ifan = 1.50 x 10-3 kg-m2, calculate the Net torque, LaTeX: \tau_{net}τ n e t, required for part a.
Physics
1 answer:
Korolek [52]3 years ago
7 0

Answer:

α=9.42 rad/s    T= 0.014 rad/s^{2}

Explanation:

Low speed= Wi=3 rps = 3*2*π rad/s= 6π rad/sec

Medium speed= Wf= 9 rps= 9*2*π rad/sec= 18 rad/sec

time= t= 4 sec

Angular acceleration=α=\frac{Wf-Wi}{t}

⇒α=(18 π - 6 π)/4

⇒α=9.42 rad/s

b).

Rotational inertia= I = 1.5*10^-3 kg-m^2

Net torque= T = I*α = (1.5*10^-3) * (9.42) rad/s^2

⇒T= 0.014 rad/s^2

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Veronika [31]

Answer:

a

Explanation:

its correct

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3 years ago
An automobile traveling 95 km/h overtakes a 1.30-km-long train traveling in the same direction on a track parallel to the road.
SOVA2 [1]

Answer:

Same direction: t=234s; d=6.175Km

Opposite direction: t=27.53s; d=0.73Km

Explanation:

If the automobile and the train are traveling in the same direction, then the automobile speed relative to the train will be v_{AT}=v_A-v_T (<em>the train must see the car advancing at a lower speed</em>), where v_A is the speed of the automobile and v_T the speed of the train.

So we have v_{AT}=(95km/h)-(75Km/h)=20Km/h.

So the train (<em>anyone in fact</em>) will watch the automobile trying to cover the lenght of the train L at that relative speed. The time required to do this will be:

t = \frac{L}{v_{AT}} = \frac{1.3Km}{20Km/h} = 0.065h=234s

And in that time the car would have traveled (<em>relative to the ground</em>):

d=v_At=(95Km/h)(0.065h)=6.175Km

If they are traveling in opposite directions, <u>we have to do all the same</u> but using v_{AT}=v_A+v_T (<em>the train must see the car advancing at a faster speed</em>), so repeating the process:

v_{AT}=(95km/h)+(75Km/h)=170Km/h

t = \frac{L}{v_{AT}} = \frac{1.3Km}{170Km/h} = 0.00765h=27.53s

d=v_At=(95Km/h)(0.00765h)=0.73Km

5 0
3 years ago
If you are given force and distance, you can determine power if you know (2 points)
dangina [55]

Answer:

The answer is time

Explanation:

So when youre given force and distance, you can determine work done

Work Done = Force × Distance travelled in the

direction of the force

Since Power = Work Done/ Time

when you know work done, and you want to find power, you will need time.

Because you have work done already, you dont need energy. Though you can use energy and time to find work too. The alternative formula for Power would be:

Power = Energy Converted/Time

4 0
3 years ago
During a neighborhood baseball game in a vacant lot, a particularly wild hit sends a 0.146 kg baseball crashing through the pane
Nonamiya [84]

Answer:

Impulse, |J| = 0.6716 kg-m/s

Force, F = 63.35 N

Explanation:

It is given that,

Mass of the baseball, m = 0.146 kg

Initial speed of the ball, u = 15.3 m/s

Final speed of the ball, v = 10.7 m/s

To find,

(a) The magnitude of this impulse.

(b) The magnitude of the average force of the glass on the ball.

Solution,

(a) Impulse of an object is equal to the change in its momentum. It is given by :

J=m(v-u)

J=0.146\ kg(10.7-15.3)\ m/s

J = -0.6716 kg-m/s

or

|J| = 0.6716 kg-m/s

(b) Another definition of impulse is given by the product of force and time of contact.

t = 0.0106 s

J=F\times \Delta t

F=\dfrac{J}{\Delta t}

F=\dfrac{0.6716\ kg-m/s}{0.0106\ s}

F = 63.35 N

Hence, this is the required solution.

6 0
3 years ago
A thin glass rod is submerged in oil. What is the critical angle for light traveling inside the rod? The index of refraction for
Alekssandra [29.7K]
When light travels from a medium with higher refractive index to a medium with lower refractive index, the critical angle is the angle of incidence above which light is reflected only (no refraction occurs), and the value of this critical angle is given by
\theta_c = \arcsin ( \frac{n_2}{n_1} )
where n2 is the refractive index of the second medium and n1 is the refractive index of the first medium.

In this problem, the first medium is the glass (n_1 = 1.50), while the second medium is oil (n_2 =1.46), therefore the critical angle is given by
\theta_c = \arcsin( \frac{1.46}{1.50} )=\arcsin(0.973)=76.7^{\circ}
7 0
3 years ago
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