An electric fan has a low speed of 3.00 rotations per second and a medium speed of 9.00 rotations per second. The fan rotates co
1 answer:
Answer:
α=9.42 rad/s T= 0.014 rad/s
Explanation:
Low speed= Wi=3 rps = 3*2*π rad/s= 6π rad/sec
Medium speed= Wf= 9 rps= 9*2*π rad/sec= 18 rad/sec
time= t= 4 sec
Angular acceleration=α=
⇒α=(18 π - 6 π)/4
⇒α=9.42 rad/s
b).
Rotational inertia= I = 1.5*10^-3 kg-m^2
Net torque= T = I*α = (1.5*10^-3) * (9.42) rad/s^2
⇒T= 0.014 rad/s^2
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Answer:
A)
B) The vector definition of E-field is
where magnitude is E = 2.66 N/m.
Explanation:
The potential of a uniformly charged rod can be found by the method of integration. We will first choose an infinitesimal part on the rod. We will compute the potential of this part at point A. Then we will integrate this potential over the entire rod.
We will use the following formula for electric potential:
Let us choose the infinitesimal part a distance 'x' from the origin. Then the distance between this point and point A is
The infinitesimal length is 'dx', and the potential of this length is dV. Let's apply the formula:
Here, the charge Q is equal to the charge density multiplied by the length. Q = λdx
Now we have to integrate this infinitesimal potential over the rod:
By using an integral table, this can be calculated:
B) The electric field can be found by a similar approach, but a different formula:
Let's apply this formula to the infinitesimal part we have chosen.
By the geometry sine and cosine terms can be found:
The x- and y-components of the E-field can be found separately by integrating the infinitesimal parts over the entire rod.
So, the final E-field is
The magnitude of the E-field is
E = 2.66 N/m