The braking force is -400 N
Explanation:
We can solve this problem by using the impulse theorem, which states that the impulse applied on the ferry (the product of force and time) is equal to its change in momentum:
where in this problem, we have:
F is the force applied by the brakes
is the time interval
m = 13,000 kg is the mass of the ferry
u = 2.0 m/s is the initial velocity
v = 0 is the final velocity
And solving for F, we find the force applied by the brakes:
where the negative sign indicates that the direction is backward.
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In series combination, resister are connected end to end and current has a single path through the circuit but the potential difference varies across each resistor. Thus we can write as,
V = V1 + V2 + V3
according to Ohm's law V = IR So,
V1 = I R1, V2 = I R2, V3 = I R3
V = I R1 + I R2 + I R3
V = I(R1+R2+R3)
V =IRe
All the individual resistances become equal to the equivalent resistance.
or Re = R1 + R2 + R3......Rn
In parallel combination, each resistor'sone is connected to the positive terminal while the other end is connected to a negative terminal. The potential difference across each resistance is the same and the current passing through them is different.
V = V1 =V2=V3
I = I1+ I2+I3
Current throught each resistor will be:
I1= V/R1 , I2 = V/R2 = I3 = V/R3
I = V (1/R1+ 1/R2+1/R3)
In case of equivalent resistance I=V/Re
V/Re = V (1/R1+ 1/R2+1/R3)
So the equivalnet resistance is the sum of all resistances
1/Re = 1/R1+ 1/R2+1/R3
Answer:
It is actually the 1st, 4th, and 5th answer choices :)
Explanation:
Answer: The total resistance in a parallel circuit is always less than any of the branch resistances. Adding more parallel resistances to the paths causes the total resistance in the circuit to decrease. As you add more and more branches to the circuit the total current will increase because Ohm's Law states that the lower the resistance, the higher the current.
Explanation:
Answer: option (D)
Explanation:
The potential energy of each of the students is given below as
P.E(student A) = mgh, where m = mass of student A, g is acceleration due to gravity and h = height of the high dive structure.
The mass of student B is twice as much as that of A, hence his mass is 2m and his potential energy is given below as
P.E ( student B) =2mgh = 2(mgh)
Recall that the relationship between potential energy and work done is that
Work done = - (change in potential)
For student A, work done = - mgh
For student B, work done = - 2mgh
From the equations above it can be seen that student B will do twice the work in getting to the high dive structure than student A hence validating option D.
