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san4es73 [151]
3 years ago
11

An electric fan has a low speed of 3.00 rotations per second and a medium speed of 9.00 rotations per second. The fan rotates co

unter-clockwise, CCW. a) The fan is running on low speed when it is switched to medium speed. It takes 4.00 seconds for the fan to reach medium speed. What is the angular acceleration, LaTeX: \alphaα? b) If the rotational inertia of the fan is Ifan = 1.50 x 10-3 kg-m2, calculate the Net torque, LaTeX: \tau_{net}τ n e t, required for part a.
Physics
1 answer:
Korolek [52]3 years ago
7 0

Answer:

α=9.42 rad/s    T= 0.014 rad/s^{2}

Explanation:

Low speed= Wi=3 rps = 3*2*π rad/s= 6π rad/sec

Medium speed= Wf= 9 rps= 9*2*π rad/sec= 18 rad/sec

time= t= 4 sec

Angular acceleration=α=\frac{Wf-Wi}{t}

⇒α=(18 π - 6 π)/4

⇒α=9.42 rad/s

b).

Rotational inertia= I = 1.5*10^-3 kg-m^2

Net torque= T = I*α = (1.5*10^-3) * (9.42) rad/s^2

⇒T= 0.014 rad/s^2

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Answer:

Voltage across the capacitor is 30 V and rate of energy across the capacitor is 0.06 W

Explanation:

As we know that the current in the circuit at given instant of time is

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V_c = 30 V

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U = \frac{q^2}{2C}

here rate of change in energy of the capacitor is given as

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\frac{dU}{dt} = (30)(2 mA)

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Answer:

Wavelength, \lambda=1.28\times 10^{-14}\ m

Explanation:

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Hence, this is the required solution.

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a car initially at 39.40 m/s accelerates at -3.00 m/s^2 how far has a car travel when it comes to a stop 9.35 seconds later
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499.523. meter

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A uniformly charged conducting sphere of 1.1 m diameter has a surface charge density of 6.2 µC/m2. (a) Find the net charge on th
ira [324]

Answer:

(a) q = 2.357 x 10⁻⁵ C

(b) Φ = 2.66 x 10⁶ N.m²/C

Explanation:

Given;

diameter of the sphere, d = 1.1 m

radius of the sphere, r = 1.1 / 2 = 0.55 m

surface charge density, σ = 6.2 µC/m²

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q = 4πr²σ

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4πr² is surface area of the sphere

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(b) the total electric flux leaving the surface of the sphere

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B. Elastic potential to kinetic energy

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