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bazaltina [42]
2 years ago
15

In a communist economy, all economic activities are controlled by . Such economies are also known as

Chemistry
1 answer:
svp [43]2 years ago
5 0

Answer:

n a communist economy, all economic activities are controlled by government . Such economies are also known as command economy

Explanation:

in this type of economy, private owners are restricted  from producing and distributing goods and services , the government controls the entire economic activities

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9. How many grams are in 2.0 x 105 molecules of carbon monoxide?
timama [110]

Answer: 9.3 x 10^ 18 g CO

Explanation:

Start by knowing that carbon monoxide is the compound CO. To convert molecules to grams, you first need to convert molecules to moles. This can be done using the conversion factor for Avogadro's Number:

(2.0 x 10^5 molecules CO) x 1 mol CO / 6.02 x 10^23 molecules CO

This cancels molecules CO.

Then, you can convert moles to grams, which is your desired quantity. You can find the number of grams for CO by looking at the periodic table and adding together their masses. C = 12 g and O = 16 g. Total of 28 g CO:

(1 mol CO) x 28 g CO / 1 mol CO

This cancels mol CO, which leaves grams CO.

5 0
2 years ago
Add a constant temperature when the volume of the gas is decreased what happens to its pressure
Margaret [11]

Answer:

<h2>Pressure will increase</h2>

Explanation:

At a constant temperature, the pressure of gas will increase proportional to the decrease in volume of the gas.

P1V1= P2V2

Decrease in volume result in increase in pressure as the equation has to hold true.

8 0
2 years ago
What is the base dissociation constant for a weak base at equilibrium, B + H2O &lt;===&gt; BH+ + OH–?
podryga [215]
Depends on what the base is. You would reference the base dissociation chart for that value.
3 0
3 years ago
Read 2 more answers
Purification of copper can be achieved by electrorefining copper from an impure copper anode onto a pure copper cathode in an el
givi [52]

Answer: The amount of time needed to plate 14.0 kg of copper onto the cathode is 295 hours

Explanation:

We are given:

Moles of electron = 1 mole

According to mole concept:

1 mole of an atom contains 6.022\times 10^{23} number of particles.

We know that:

Charge on 1 electron = 1.6\times 10^{-19}C

Charge on 1 mole of electrons = 1.6\times 10^{-19}\times 6.022\times 10^{23}=96500C

Cu^{2+}+2e^-\rightarrow Cu

2\times 96500=193000C is passed to deposit = 1 mole of copper

63.5 g of copper is deposited by = 193000 C

14\times 1000g=14000g of copper is deposited by =\frac{193000}{63.5}\times 14000=42551181 C

To calculate the time required, we use the equation:

I=\frac{q}{t}

where,

I = current passed = 40.0 A

q = total charge = 42551181 C

t = time required = ?

Putting values in above equation, we get:

40.0=\frac{42551181 C}{t}\\\\t=1063779sec

Converting this into hours, we use the conversion factor:

1 hr = 3600 seconds

So, 1063779s\times \frac{1hr}{3600s}=295hr

Hence, the amount of time needed to plate 14.0 kg of copper onto the cathode is 295 hours

3 0
3 years ago
At constant force, acceleration varies (directly, inversely) with mass. When subjected to the same amount of net external force,
lora16 [44]

Answer:

I don't know the ans please search on the Google you will get

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7 0
2 years ago
Read 2 more answers
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