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Ksenya-84 [330]
3 years ago
6

Calculate the value deltaG°​

Chemistry
1 answer:
atroni [7]3 years ago
4 0

Answer:

ΔG=ΔG0+RTlnQ where Q is the ratio of concentrations (or activities) of the products divided by the reactants. Under standard conditions Q=1 and ΔG=ΔG0 . Under equilibrium conditions, Q=K and ΔG=0 so ΔG0=−RTlnK . Then calculate the ΔH and ΔS for the reaction and the rest of the procedure is unchanged.

Explanation:

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Can someone please help by filling out this table?
tamaranim1 [39]

Answer:

Lithium looses one electron.

The charge - Li^{+} - Cation

Nitrogen gains three electrons - Ni^{3-} - Anion

Boron losses three electron.

The charge - B^{3+} - Cation

Explanation:

Lithium looses one electron.

The charge - Li^{+} - Cation

Nitrogen gains three electrons - Ni^{3-} - Anion

Boron losses three electron.

The charge - B^{3+} - Cation

The complete table is as follows.

5 0
3 years ago
What is the percent by volume of 12.5 mL of ethanol in 250 mL of water?<br> 3%<br> 5%<br> 4%<br> 6%
Fittoniya [83]
The answer for your question is 5%
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Explanation:

6 0
3 years ago
A substance dissolves in water by breaking up into smaller pieces. these pieces of the same substance spread throughout the wate
photoshop1234 [79]
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Photon 
6 0
4 years ago
Silver has a density of 10.5g/cm to the 3rd and gold has density of 9.3g/cm to the 3rd. Which would have a greater mass, 5cm to
Akimi4 [234]
The density of gold is 19.3 g/cm³

Ag= silver
Au= gold.
density (Ag)=10.5 g/cm³.
density (Au)=19.3 g/cm³

We have to calculate the mass of 5 cm³ silver:

10.5 g---------------------1 cm³
x---------------------------  5 cm³

x=(10.5 g  * 5 cm³) / 1cm³ ≈52.5 g

And we have to calculate the mass of 5 g gold.

19.3 g------------------------1 cm³
x-------------------------------5 cm³

x=(19.3 g * 5 cm³) / 1cm³≈96.5  g

Then 5 cm³ silver are 52.5 g of mass, and 5 cm³ gold are 96.5 g of mass, therefore,  gold would have a greater mass than silver.

answer:5 cm³ gold would have a greater mass than 5 cm³ silver.
3 0
4 years ago
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