All categories

3 years ago

Calculate the force between two touching grape fruits each with a radius of 0.08 meters and a mass of 0.45 kilograms

Physics

2 answers:

Bas_tet [7]3 years ago

6 0

Newton's formula for the force of gravity:

   F = G · M₁ · M₂ / D²

Here's what the letters mean:

F . . . the strength of the gravitational force between two objects
G . . . the universal gravitational constant for SI units: 6.67 x 10⁻¹¹ N·m²/kg²
M₁ . . . the mass of one object
M₂ . . . the mass of the other object
D . . . the distance between the centers of the objects

If the radius of each grapefruit is 0.08 meter and their skins are touching,
then their centers are 0.16 meter apart.

The force between them is

    F = G · M₁ · M₂ / D²

    = (6.67 x 10⁻¹¹ N·m² / kg²) · (0.45 kg) · (0.45 kg) / (0.16 m)²

   = (6.67 x 10⁻¹¹ · 0.45 · 0.45) / (0.0256) N·m²·kg²/kg²·m²

   = ( 1.35 x 10⁻¹¹) / (0.0256) Newton

   = 5.28 x 10⁻¹⁰ Newton (rounded)

(about 0.0000000019 ounce)

Volgvan3 years ago

3 0

Hope it cleared your doubt.

You might be interested in

Suppose a police officer is 1/2 mile south of an intersection, driving north towards the intersection at 40 mph. At the same tim

blagie [28]

Answer:

75.36 mph

Explanation:

The distance between the other car and the intersection is,

$x=x_{0}+V t \\ x=\frac{1}{2}+V t$

The distance between the police car and the intersection is,

$y=y_{0}+V t$

$y=\frac{1}{2}-40 t$

(Negative sign indicates that he is moving towards the intersection)

Therefore the distance between them is given by,

$z^{2}=x^{2}+y^{2}(\text { Using Phythogorous theorem })$

$z^{2}=\left(\frac{1}{2}+V t\right)^{2}+\left(\frac{1}{2}-40 t\right)^{2} \ldots \ldots \ldots(1)$

The rate of change is,

$2 z \frac{d z}{d t}=2\left(\frac{1}{2}+V t\right) V+2\left(\frac{1}{2}-40 t\right)(-40)$

$2 z \frac{d z}{d t}=V+2 V^{2} t-40+3200 t \ldots \ldots \ldots$

Now finding $z$ when $t=0,$ from (1) we have

$z^{2}=\left(\frac{1}{2}+V(0)\right)^{2}+\left(\frac{1}{2}-40(0)\right)^{2}$

$z^{2}=\frac{1}{4}+\frac{1}{4}=\frac{1}{2} \\ z=\sqrt{\frac{1}{2}} \approx 0.7071$

The officer's radar gun indicates 25 mph pointed at the other car then, $\frac{d z}{d t}=25$ when $t=0,$ from

From (2) we get

$2(0.7071)(25)=V+2 V^{2}(0)-40+3200(0)$

$2(0.7071)(25)=V+2 V^{2}(0)-40$

$35.36=V-40$

$V=35.36+40=75.36$

Hence the speed of the car is $75.36 mph$

7 0

3 years ago

Please help, and show steps. Thank you very much!

Vikentia [17]

V = 8 * 10^2 km/h = 800km/h
S= 1,8* 10^3 km = 1800km
t = ?
v = S/t
t = S/v
t = 1800km/ 800km/h
t ≈ 2,25h (135min)

6 0

4 years ago

Describe the shape of a convex lens and explain what it does to light.

alexira [117]

Convex lenses are thicker at the centers than the edges, they are known as the converging lenses. Rays of light that pass through the lens are brought closer together (they converge). When rays of light that are parallel pass through a convex lens they are refracted, the refracted rays converge at one point called the principal focus.

4 0

3 years ago

Which one of the following types of electromagnetic wave travels through space the fastest?

Setler [38]

Answer:

As a result, light travels fastest in empty space, and travels slowest in solids. In glass, for example, light travels about 197,000 km/s.

Explanation:

4 0

2 years ago

A shopping cart given an initial velocity of 2.0 m/s undergoes a constant acceleration to a velocity of 13 m/s. What is the magn

olga55 [171]

Answer:

The acceleration is a = 2.75 [m/s^2]

Explanation:

In order to solve this problem we must use kinematics equations.

$v_{f} = v_{i} + a*t\\$

where:

Vf = final velocity = 13 [m/s]

Vi = initial velocity = 2 [m/s]

a = acceleration [m/s^2]

t = time = 4 [s]

Now replacing:

13 = 2 + (4*a)

(13 - 2) = 4*a

a = 2.75 [m/s^2]

5 0

4 years ago