The volume of CO₂ at STP = 2.8 L
<h3>Further explanation</h3>
Given
21 gram of sodium hydrogen carbonate-NaHCO₃
Required
Volume of CO₂
Solution
The decomposition of sodium bicarbonate into sodium carbonate, carbon dioxide, and water :
<em>
2 NaHCO₃(s) → Na₂CO₃(s) + CO₂(g) + H₂O(g)</em>
mol of NaHCO₃ :
= mass : MW NaHCO₃
= 21 g : 84 g/mol
= 0.25
From the equation, mol ratio of NaHCO₃(s) :CO₂(g) = 2 : 1, so mol CO₂ :
= 1/2 x mol NaHCO₃
= 1/2 x 0.25
= 0.125
At STP, 1 mol gas = 22.4 L, so for 0.125 mol :
= 0.125 x 22.4 L
= 2.8 L
Answer:
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Explanation:
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<em>Tori </em>
Answer:
199 g
Explanation:
Law of conservation of mass:
According to the law of conservation mass, mass can neither be created nor destroyed in a chemical equation.
Explanation:
This law was given by french chemist Antoine Lavoisier in 1789. According to this law mass of reactant and mass of product must be equal, because masses are not created or destroyed in a chemical reaction.
For example:
In given reaction:
Reactant A = 115 g
Reactant B = 84 g
Product AB = ?
A + B → AB
115 g + 84 g = 199 g
199 g = 199 g
Answer:
Relative molecular of the compound or infomation like vapour density, volume occupied by a known mass of its vapour at stp, etc
Explanation:
The molecular mass of a compound is twice its vapour density. We can find the molecular formula using the relationship below:
- Empirical formula is the simplest formula of a compound. It repeats itself "n" times to become a molecular formula i.e (EF)ₙ = MF...... n is the number of times the empirical formula presents in a mole of the compound.
- Most times, n is a whole number like 1,2,3,.....
