Carbon can make four bonds. Since it is doubly bonded carbon, it means it can make two more bonds. So, two more hydrogen atoms could help in bond formation.
Two H atoms are attached to each carbon.
Answer:
A. 2H₂O₂ → 2H₂O + O₂
Explanation:
- 2. H₂O₂ + OI⁻ → H₂O + O₂ + I⁻
If we <u>make a net sum of both reactions</u>, we're left with:
- H₂O₂ + I⁻ + H₂O₂ + OI⁻ → H₂O + OI⁻ + H₂O + O₂ + I⁻
Grouping species:
- 2H₂O₂ + OI⁻ + I⁻ → 2H₂O + OI⁻ + O₂ + I⁻
There is OI⁻ at both sides, so it is eliminated -same goes for the catalyst, I⁻-.
Thus the answer is option A.
The volume of the stock solution that has a concentration of 1.5 M SO2 and is diluted to a 0.54 M solution with a volume of 0.18 L is 0.065L.
<h3>How to calculate volume?</h3>
The concentration of a solution can be calculated using the following formula:
C1V1 = C2V2
Where;
- C1 = initial concentration = 1.5M
- C2 = final concentration = 0.54M
- V1 = initial volume = ?
- V2 = final volume = 0.18L
1.5 × V1 = 0.54 × 0.18
1.5V1 = 0.0972
V1 = 0.0972 ÷ 1.5
V1 = 0.065L
Therefore, the volume of the stock solution that has a concentration of 1.5 M SO2 and is diluted to a 0.54 M solution with a volume of 0.18 L is 0.065L.
Learn more about volume at: brainly.com/question/1578538
Answer:
presence or absence of a nucleus
Explanation:
These classification of organisms into broad domains is based on the present or absence of nucleus in the cell of an organism.
The archaea are prokaryotes and they lack a distinct cellular nuclei.
Bacteria are similar to archaea but bacteria have only one RNA polymerase
Eukarya have true nucleus and membrane bound organelles .
So, the variations in their cells are used to classify organisms into the broad categories
