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4 years ago

Four friends were born in consecutive years. The sum of their ages is 62. What is the age of the oldest friend?

Mathematics

1 answer:

marin [14]4 years ago

7 0

The ages range from 62, 63, 64, 65 oldest friend age is 65

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Given equations A and B as 2/5x+y=12 and 5/2y-x=6 respectively which expression will eliminate the variable X a) 5/2A+2/5B b)5/2

frutty [35]

Answer:

C) $A+\frac{2}{5}B$

Step-by-step explanation:

Given Equations:

A) $\frac{2}{5}x+y=12$

B) $\frac{5}{2}y-x=6$

In order to eliminate $x$ we need to multiply $\frac{2}{5}$ to equation B and add it to A.

Multiplying $\frac{2}{5}$ to B.

⇒ $\frac{2}{5}\times (\frac{5}{2}y-x)=\frac{2}{5}\times 6$

⇒ $(\frac{2}{5}\times\frac{5}{2}y)-(\frac{2}{5}x)=\frac{12}{5}$

⇒ $y-\frac{2}{5}x=\frac{12}{5}$

Adding it equation A.

$\frac{2}{5}x+y=12$

+ $-\frac{2}{5}x+y=\frac{12}{5}$

We get $2y=\frac{72}{5}$

Thus $x$ is eliminated.

So, the expression used to eliminate $x$ is:

$A+\frac{2}{5}B$

4 0

3 years ago

Answer four and five please

mr_godi [17]

You find out what you have to do to get three then one and so on

7 0

3 years ago

For what real values of does the quadratic 12x^2+k*x+27=0 have nonreal roots

icang [17]

Step-by-step explanation:

Discriminant : k² - 4(12)(27) < 0

So k² - 1296 < 0, -36 < k < 36.

3 0

3 years ago

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Which expression is equivalent to

Maksim231197 [3]

Answer:

Step-by-step explanation:

3 0

3 years ago

One third of eleven sixteenths

raketka [301]

1/3 times 11/16 equals 11/48

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3 years ago

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