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Dennis_Churaev [7]

4 years ago

7

What role do plants serve in the oxygen cycle

1 answer:

kodGreya [7K]4 years ago

4 0

Plants,such as trees poduce oxygen to help animals like insects or humans can bresth snd surviave.

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Setler79 [48]

They use a spectrograph so the answer would be B.

7 0

3 years ago

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I HAVE A PHYSICS TEST, ITS 25 QUESTIONS AND I HAVE ABOUT AN HOUR TO SOLVE IT. PLEASE IF YOU’RE GOOD AT PHYSICS CONTACT ME ASAP

Katena32 [7]

Answer:

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5 0

3 years ago

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Person is lifting a 250 N dumbbell. The weight is 30 cm from the pivot point of the elbow. What force must be exerted five from

qwelly [4]

Refer to the diagram shown below.

The force, F, is applied at 5 cm from the elbow.

For dynamic equilibrium, the sum of moments about the elbow is zero.
Take moments about the elbow.
(5 cm)*(F N) - (30 cm)*(250 N) = 0
F = (30*250)/5 = 1500 N

Answer: 1500 N

4 0

3 years ago

Observe yourself breathing and count the number of times you inhale per second. During each breath you probably inhale 0.66 L of

Pavel [41]

To solve this exercise it is necessary to apply the concepts related to Robert Boyle's law where:

$PV=nRT$

Where,

P = Pressure

V = Volume

T = Temperature

n = amount of substance

R = Ideal gas constant

We start by calculating the volume of inhaled O_2 for it:

$V = 21\% * 0.66L$

$V = 0.1386L$

Our values are given as

P = 1atm

T=293K $R = 0.083145kJ*mol^{-1}K^{-1}$

Using the equation to find n, we have:

$PV=nRT$

$n = \frac{PV}{RT}$

$n = \frac{(1)(0.1386)}{(0.0821)(293)}$

$n = 5.761*10^{-3}mol$

Number of molecules would be found through Avogadro number, then

$\#Molecules = 5.761*10^{-3}*6.022*10^{23}$

$\#Molecules = 3.469*10^{21} molecules$

7 0

3 years ago

A basketball player jumps straight upward. After 0,625 s, she is 0.441 m above the ground. What is her initial velocity?????????

Lunna [17]

Answer:

v₀ = 3.77 [m/s]

Explanation:

This problem can be solved in a simple way by means of the following equation of kinematics.

$y=y_{o}+v_{o}*t+\frac{1}{2}*g*t^{2}$

where:

y - yo = 0.441 [m]

Vo = initial velocity [m/s]

g = gravity acceleration = 9.81 [m/s²]

t = time = 0.625 [s]

$0.441 = v_{o}*(0.625)-\frac{1}{2} *9.81*(0.625)^{2} \\2.357 = v_{o}*0.625\\v_{o}=3.77[m/s]$

Note: The sign of the acceleration is negative since the movement of the basketball player is against of the gravity acceleration.

4 0

3 years ago