Answer: <em>The number placed in front of a compound to balance a chemical reaction is called </em><em><u>coefficient</u></em>.
Explanation:
Assume this general form for a <em>chemical equation</em>:
- <em>a</em>A + <em>b</em>B → <em>c</em>C + <em>d</em>D
The letters <em>a, b, c, </em>and <em>d,</em> in front of each compound A, B, C, and D, are called coefficients and indicate the number of formula units (molecules or ions) that take part in the equation.
Those coefficients are needed to <em>balance the equation</em> and ensure compliance with the law of mass conservation.
This example shows it:
- Word equation: hydrogen + oxygen yields water
- Chemical equation: H₂ (g) + O₂(g) → H₂O(g)
- Balance, adding the coefficients so that the number of each kind of atoms is the same on the left and the right of the chemical equation:
H₂ (g) + 2O₂(g) → 2H₂O(g)
In that equation:
- The coefficient of H₂ (g) on the left is 1 (it is not written)
- The coefficient of O₂(g) on the left is 2
- The coefficient of H₂O(g) on the right is 2
You read it as: 1 mole of gaseous hydrogen and 2 moles of gaseous oxygen yield 2 moles of water vapor.
Answer:
C : Television
Explanation:
We should click on button from where the wire gets connected to the tv and operate. TV needs electric conductor for the flow of current .
Hey there!:
Molar mass CO2 = 44.01 g/mol
44.01 g CO2 ------------------- 6.02*10²² molecules CO2
88 g CO2 ------------------------ y
y = 88 * ( 6.02*10²² ) / 44.01
y = 5.29*10²⁵ / 44.01
y = 1.2 * 10²⁴ molecules of CO2
Answer A
Hope that helps!
When we have the balanced reaction equation is:
H2(g) + CO2(g) ↔ H2O(g) + CO (g)
a) first, to calculate ΔG° for the reaction:
we will use this formula:
ΔG° = -RT㏑Kp
when R is R- rydberg constant = 8.314J/mol.K
and T is the temperature in Kelvin = 2000 K
and Kp = 4.4
so, by substitution:
ΔG° = - 8.314 *2000 *㏑4.4
= - 24624 J/mol = - 24.6 KJ/mol
b) to calculate ΔG so, we will use this formula:
ΔG = ΔG° + RT㏑Qp
So we need first, to get Qp from the reaction equation:
when Qp = P products / P reactants
= PH2O*PCO / PH2 * PCO2
= (0.66 atm * 1.2 atm) / (0.25 * 0.78)
= 4.1
so by substitution:
ΔG = -24624 + 8.314*2000*㏑4.1
= -1162 J/mol = - 1.16 KJ/mol
