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rodikova [14]
2 years ago
10

In an ideal reheat cycle, steam is generated at 6.3 Mpa, 450 deg. C and partially expands to 0.84 Mpa. At this point, the steam

is withdrawn and passed through a reheater. It re-enters the turbine at 0.84 Mpa and 480 deg. C. Complete expansion now occurs to the condenser pressure of 0.02 Mpa. Find the following: a. Enthalpies b. Total heat added and rejected c. Total turbine work and pump work d. Net cycle work e. Cycle efficiency and engine efficiency​
Engineering
1 answer:
AURORKA [14]2 years ago
7 0
300 squeare meter 60deegree
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Water flows through a pipe of 100 mm at the rate of 0.9 m3 per minute at section A. It tapers to 50mm diameter at B, A being 1.5
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Answer:

The velocities in points A and B are 1.9 and 7.63 m/s respectively. The Pressure at point B is 28 Kpa.

Explanation:

Assuming the fluid to be incompressible we can apply for the continuity equation for fluids:

Aa.Va=Ab.Vb=Q

Where A, V and Q are the areas, velocities and volume rate respectively. For section A and B the areas are:

Aa=\frac{pi.Da^2}{4}= \frac{\pi.(0.1m)^2}{4}=7.85*10^{-3}\ m^3

Ab=\frac{pi.Db^2}{4}= \frac{\pi.(0.05m)^2}{4}=1.95*10^{-3}\ m^3

Using the volume rate:

Va=\frac{Q}{Aa}=\frac{0.9m^3}{7.85*10^{-3}\ m^3} = 1.9\ m/s

Vb = \frac{Q}{Ab}= \frac{0.9m^3}{1.96*10^{-3}\ m^3} = 7.63\ m/s

Assuming no losses, the energy equation for fluids can be written as:

Pa+\frac{1}{2}pa.Va^2+pa.g.za=Pb+\frac{1}{2}pb.Vb^2+pb.g.zb

Here P, V, p, z and g represent the pressure, velocities, height and gravity acceleration. Considering the zero height level at point A and solving for Pb:

Pb=Pa+\frac{1}{2}pa(Va^2-Vb^2)-pa.g.za

Knowing the manometric pressure in point A of 70kPa, the height at point B of 1.5 meters, the density of water of 1000 kg/m^3 and the velocities calculated, the pressure at B results:

Pb = 70000Pa+ \frac{1}{2}*1000\ \frac{kg}{m^3}*((1.9m/s)^2 - (7.63m/s)^2) - 1000\frac{kg}{m^3}*9,81\frac{m}{s^2}*1.5m

Pb = 70000\ Pa-27303\ Pa - 14715\ Pa

Pb = 27,996\ Pa = 28\ kPa

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2 years ago
The pressure gauge on a tank of CO2 used to fill Dora-water bottles reads 51.0 psi.
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Known :

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2 years ago
A rectangular concrete (n=0.013) channel 20 feet wide, on a 2.5% slope, is discharging 400 ft3 /sec into a stilling basin. The s
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Answer:

Length of stilling basin = 32.9 feet

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Explanation:

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here, A is the flow area and P is the wetted perimeter

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<u>d = 1.42 feet</u>

<u></u>

Depth of stilling channel before the jump will be = d1 =  8 feet

Depth of stilling channel after the jump will be = d2 = 1.42 feet

Length of stilling basin = 5(d2 - d1)

                                      = 5( 8 - 1.42)

<u>Length of stilling basin = 32.9 feet </u>

Now calculating the height of end sill:

Jump height = (8 - 1.42)

<u>Height of end sill = 6.58 feet</u>

8 0
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