In an ideal reheat cycle, steam is generated at 6.3 Mpa, 450 deg. C and partially expands to 0.84 Mpa. At this point, the steam
1 answer:
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Answer:
2543 k
Explanation:
This problem can be resolved by applying the first law of thermodynamics
<u>Determine the adiabatic flame temperature</u> when the furnace is operating at a mass air-fuel ratio of 16 for air preheated to 600 K
attached below is a detailed solution
cp = 1200
Answer:
(A) Maximum voltage will be equal to 333.194 volt
(B) Current will be leading by an angle 54.70
Explanation:
We have given maximum current in the circuit
Inductance of the inductor
Capacitance
Frequency is given f = 44 Hz
Resistance R = 500 ohm
Inductive reactance will be
Capacitive reactance will be equal to
Impedance of the circuit will be
So maximum voltage will be
(B) Phase difference will be given as
So current will be leading by an angle 54.70
Answer:
ΔT= 11.94 °C
Explanation:
Given that
mass of water = 10 kh
Time t= 15 min
Heat lot from water = 400 KJ
Heat input to the water = 1 KW
Heat input the water= 1 x 15 x 60
=900 KJ
By heat balancing
Heat supply - heat rejected = Heat gain by water
As we know that heat capacity of water
Now by putting the values
900 - 400 = 10 x 4.187 x ΔT
So rise in temperature of water ΔT= 11.94 °C