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Maru [420]
3 years ago
15

Georgia Tech is committed to creating solutions to some of the world’s most pressing challenges. Tell us how you have improved o

r hope to improve the human condition in your community.
Engineering
1 answer:
Kaylis [27]3 years ago
6 0

Answer:

Georgia Tech is committed to WGAR 53566 THE ANSWER IS JELLY IS KING AND THE JELLY IS KING AND  hope to improve the human condition in your community.

Explanation:

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A cooling system load is 96,000 BTUh sensible. How much chilled air is required to satisfy the load if the system is designed fo
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Answer:

For 20^{\circ} - 5.556 lb/s

For 15^{\circ} - 7.4047 lb/s

Solution:

As per the question:

System Load = 96000 Btuh

Temperature, T = 20^{\circ}

Temperature rise, T' = 15^{\circ}

Now,

The system load is taken to be at constant pressure, then:

Specific heat of air, C_{p} = 0.24 btu/lb ^{\circ}F

Now, for a rise of 20^{\circ} in temeprature:

\dot{m}C_{p}\Delta T = 96000

\dot{m} = \frac{96000}{C_{p}\Delta T} = \frac{96000}{0.24\times 20} = 20000 lb/h = \frac{20000}{3600} = 5.556 lb/s

Now, for 15^{\circ}:

\dot{m}C_{p}\Delta T = 96000

\dot{m} = \frac{96000}{C_{p}\Delta T} = \frac{96000}{0.24\times 15} = 26666.667 lb/h = \frac{26666.667}{3600} = 7.4074 lb/s

4 0
3 years ago
For an isotropic material, E and ν are often chosen as the two independent engineering constants. There are other elastic consta
pav-90 [236]

Answer:

khgy

Explanation:

nbv

8 0
3 years ago
A pipe 100 mm dia and 1 km long is to carry water from a reservoir to a village of 1000 people consuming 200 l/person/day. The p
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Answer:

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3 years ago
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A gas enters a compressor that provides a pressure ratio (exit pressure to inlet pressure) equal to 8. If a gage indicates the g
olga55 [171]

Answer:

P_2_{abs}=160\ psia (absolute).

Explanation:

Given that

Pressure ratio r

r=8

r=\dfrac{P_2_{abs}}{P_1_{abs}}

  8=\dfrac{P_2_{abs}}{P_1_{abs}}                                  -----1

P₁(gauge) = 5.5 psig

We know that

Absolute pressure = Atmospheric pressure  + Gauge  pressure

Given that

Atmospheric pressure = 14.5 lbf/in²

P₁(abs) = 14.5 + 5.5  psia

P₁(abs) =20 psia

Now by putting the values in the above equation 1

8=\dfrac{P_2_{abs}}{20}

P_2_{abs}=8\times 20\ psia

P_2_{abs}=160\ psia

Therefore the exit gas pressure will be 160 psia (absolute).

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3 years ago
can anyone give me tips on adding HP to my 2014 dodge charger SE? it uses the 3.6L220 CI 24 valve v6 vvt (variable valve timing)
marissa [1.9K]
<h2>ANSWER</h2><h2></h2>

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