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Sever21 [200]
4 years ago
5

You leave for school late when you are pulled over by a police officer for speeding. He clocks you at 52 mi/hr . What is your sp

eed in cm/sec? (1.609 km = 1 mile). You must solve the problem using dimensional analysis. All work must be shown with proper units and significant figures...HURRYYY!!
Chemistry
1 answer:
yawa3891 [41]4 years ago
3 0

Answer:

Explanation:

The maximum speed limit in Prince Edward Island

unless otherwise posted is 80 kilometres per hour

(km/h). The basic speed limits are:

• 40 km/h (25 mph) in most municipalities

(municipalities may establish the maximum

speed limit within their boundaries);

• 50 km/h (30 mph) in urban areas;

• 60 km/h (40 mph) in school zones designated as

such by the erection of signs at the entrance and

the exit, between 8 a.m. and 5 p.m. when

children are present on or near the highway on

school days;

• 80 km/h (50 mph) on most provincial highways;

and

• 90 km/h (55 mph) on the TransCanada and

other designated highways.

Posted speed limits indicate the maximum safe

speed under favourable driving conditions.

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The answer is D
6.00 M. I just took the test 
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How do machines transfer and convert energy
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What process is most likely to immediately follow the replication of DNA?
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The process is replication

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3 years ago
A sample that weighs 103.75 g is a mixture of 30% helium atoms and 70% krypton atoms. How many particles are present in the samp
aalyn [17]
1) we calculate the molar mass of He (helium) and Kr (Krypton).
atomic mass (He)=4 u
atomic mas (Kr)=83.8 u

Therefore the molar mass will be:
molar mass(He)=4 g/mol
molar mass(Kr)=83.8 g/mol.

1) We can find  the next equation:
mass=molar mass  x number of moles.

x=number of moles of helium
y=number of moles of helium. 

(4 g/mol) x  +(83.8 g/mol)y=103.75 g
Therefore, we have the next equation:

(1)

4x+83.8y=103.75


2) We can find other equation:

We have 30% helium atoms and 70% Kryptum atoms, therefore we have 30% Helium moles and 70% of Krypton moles.

1 mol  is always 6.022 * 10²³ atoms or molecules, (in this case atoms).

Then:
x=number of moles of helium
y=number of moles of helium.
(x+y)=number of moles of our sample.

x=30% of (x+y)

Therefore, we have this other equation:
(2)

x=0.3(x+y)


With the equations(1) and (2), we have the next system of equations:

4x+83.8y=103.75

x=0.3(x+y)  ⇒ x=0.3x+0.3y  ⇒    x-0.3x=0.3y  ⇒ 0.7 x=0.3y ⇒ x=0.3y/0.7
⇒x=3y/7

We solve this system of equations by substitution method.
x=3y/7

4(3y/7)+83.8y=103.75
lower common multiple)7
12y+586.6y=726.25
598.6y=726.25
y=1.21

x=3y/7=3(1.21)/7=0.52

We have 0.52 moles of  helium and 1.21 moles of Krypton.

1 mol=6.022 * 10²³ atoms

Total number of particles=(6.022 *10²³ atoms /1 mol) (number of moles of He+ number of moles of Kr).

Total number of particles=6.022 * 10²³ (0.52+1.21)=6.022 * 10²³ (1.73)=
=1.044 * 10²⁴ atoms.

Answer: The sample have 1.044 * 10²⁴ atoms.
6 0
4 years ago
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The initial concentration of reactant in a first-order reaction is 0.27 M. The rate constant for the reaction is 0.75 s−1. What
e-lub [12.9K]

Answer:

≈ 0.10M

Explanation:

[A]o = 0.27M

Rate constant, k = 0.75 s−1

[A] = ?

time, t = 1.3

Integrated formular for a first order reaction is given as;

ln[A] = ln[A]o − kt

ln[A] = ln(0.27) - 0.75(1.3)

ln[A] = -1.309 - 0.975

ln[A] = -2.284

[A] = 0.1019M ≈ 0.10M

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4 years ago
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