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2 years ago

What is/are converted into carbon dioxide , water, and energy in aerobic respiration

Chemistry

2 answers:

harina [27]2 years ago

8 0

The answer is GLUCOSE.

Lana71 [14]2 years ago

3 0

Cellular respiration involves breakdown of glucose into carbon dioxide and water in presence of oxygen, releasing energy. ... ATP molecule is converted into ADP molecule, whenever energy is needed for any metabolic reaction or activity. The energy stored in it is released to be used in metabolic reaction.

Hope this helps! So sorry if I'm wrong

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According to the kinetic theory of motion everything is made of particles and all particles are?

melisa1 [442]

All particles are in motion.

5 0

2 years ago

A block of wood has the mass of 180 grams.it is 10 cm long,6 cm wide and 4 cm thick.what is it’s density?

DochEvi [55]

Answer:

0.75 g/cm³

Explanation:

Given data:

Mass of wooden block = 180 g

Length of block = 10 cm

Width of block = 6 cm

Height or thickness = 4 cm

Density of block = ?

Solution:

Volume of block = height × length × width

Volume of block = 4 cm × 10 cm× 6 cm

Volume of block = 240 cm³

Density of block:

density = mass/ volume

d = 180 g/ 240 cm³

d = 0.75 g/cm³

4 0

2 years ago

The atomic number of an atom is always equal to the number of its what ??

Marianna [84]

The answer is protons and electrons! Hope this helps :D

3 0

2 years ago

Read 2 more answers

A racing car travels 340 miles in 120 minutes. what speed is traveling at?

Papessa [141]

Answer:

It is traveling at 170 miles per hour.

Explanation:

divide 340 by 2 because right now it's at 340 miles per two hours.

You get 170 miles per hour.

4 0

2 years ago

The pressure of a sample of helium in a 200. ml container is 2.0 atm. If the helium is compressed to a pressure of 40. atm witho

Crank

Answer:

$V_2=10mL$

Explanation:

Hello there!

In this case, according to the given information, it will be possible for us to solve this problem by using the Boyle's law as an inversely proportional relationship between pressure and volume:

$P_2V_2=P_1V_1$

In such a way, we solve for the final volume, V2, and plug in the initial volume and pressure and final pressure to obtain:

$V_2=\frac{P_1V_1}{P_2} \\\\V_2=\frac{2.0atm*200.mL}{40.atm}\\\\V_2=10mL$

Regards!

5 0

2 years ago