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3 years ago

What would happen if N2 were added to N2(g) + O2(g) = 2NO(9) at

Chemistry

1 answer:

DerKrebs [107]3 years ago

4 0

Balanced chemical equation is :

$N_2(g)+O_2(g)-->2NO(g)$

It is given that the equation is in equilibrium.

We need to find what will happen if we add more $N_2$ is added .

By Le Chatelier's principle :

Changing the concentration of a chemical will shift the equilibrium to the side that would counter that change in concentration.

It means production of the side where content is added will decrease and concentration on other side will increase .

So , more NO would form .

Therefore, option B. is correct.

Hence, this is the required solution.

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Explain hydrophobic and hydrophylic

Alika [10]

Answer:

Something defined as hydrophilic is actually attracted to water, while something that is hydrophobic resists water.

Explanation:

I hope it's help u :)

5 0

3 years ago

Read 2 more answers

Within a period, the nuclear charge increases as you move from left to right across the

a_sh-v [17]

Answer:

The answer is Ionization energy.

Explanation:

Ionization Energy. The ionization energy tends to increase as one moves from left to right across a given period or up a group in the periodic table.

3 0

3 years ago

Consider the reaction below for which K = 78.2 atm-1. A(g) + B(g) ↔ C(g) Assume that 0.386 mol C(g) is placed in the cylinder re

borishaifa [10]

Answer:

1.65 L

Explanation:

The equation for the reaction is given as:

A + B ⇄ C

where;

numbers of moles = 0.386 mol C (g)

Volume = 7.29 L

Molar concentration of C = $\frac{0.386}{7.29}$

= 0.053 M

A + B ⇄ C

Initial 0 0 0.530

Change +x +x - x

Equilibrium x x (0.0530 - x)

$K = \frac{[C]}{[A][B]}$

where

K is given as ; 78.2 atm-1.

So, we have:

$78.2=\frac{[0.0530-x]}{[x][x]}$

$78.2= \frac{(0.0530-x)}{(x^2)}$

$78.2x^2= 0.0530-x$

$78.2x^2+x-0.0530=0$

Using quadratic formula;

$\frac{-b+/-\sqrt{b^2-4ac} }{2a}$

where; a = 78.2 ; b = 1 ; c= - 0.0530

= $\frac{-b+\sqrt{b^2-4ac} }{2a}$ or $\frac{-b-\sqrt{b^2-4ac} }{2a}$

= $\frac{-(1)+\sqrt{(1)^2-4(78.2)(-0.0530)} }{2(78.2)}$ or $\frac{-(1)-\sqrt{(1)^2-4(78.2)(-0.0530)} }{2(78.2)}$

= 0.0204 or -0.0332

Going by the positive value; we have:

x = 0.0204

[A] = 0.0204

[B] = 0.0204

[C] = 0.0530 - x

= 0.0530 - 0.0204

= 0.0326

Total number of moles at equilibrium = 0.0204 + 0.0204 + 0.0326

= 0.0734

Finally, we can calculate the volume of the cylinder at equilibrium using the ideal gas; PV =nRT

if we make V the subject of the formula; we have:

$V = \frac{nRT}{P}$

where;

P (pressure) = 1 atm

n (number of moles) = 0.0734 mole

R (rate constant) = 0.0821 L-atm/mol-K

T = 273.15 K (fixed constant temperature )

V (volume) = ???

$V=\frac{(0.0734*0.0821*273.15)}{(1.00)}$

V = 1.64604

V ≅ 1.65 L

3 0

3 years ago

Which Ion has the same electron configuration as an Ar atom

Troyanec [42]

Ar (argon) has 18 electrons

Cl- would give you 18 electrons
F- would give you 10 electrons
Li+ would give you 2 electrons
Na+ would give you 10 electrons

Cl- would be the correct answer

7 0

3 years ago

Hershey and Chase grew some T2 phages in 32P-containing medium and then used that phage to infect a bacterial culture. After the

Ainat [17]

Answer:

The pellet fraction will be most radioactive because the heavy protein part of ghost will be present in the the pellet fraction.

Explanation:

supernatant can be defined as a liquid part that lies above the sediment of the centrifuge tube on the other hand pallet is a solid material present at the bottom end of the centrifuge tube.

As protein molecules in the given experiment is radio labelled that"s why the pellet fraction will be radio labeling part because the heavy protein molecules will be present in the pellet fraction.

5 0

4 years ago