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Inessa [10]
3 years ago
5

Can anyone help me if possible?

Chemistry
1 answer:
Studentka2010 [4]3 years ago
6 0
Well since I can't sketch anything up on this app no but it is very simple ask a family member to help sketch it out it won't be hard
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When you transferred the hot metal from the boiling water and into the calorimeter (coffee cup), if the thermometer touched the
sergey [27]

When you transferred the hot metal from the boiling water and into the calorimeter,  The effect will be

  • Change in temp is positive
  • Temp of metal V, dT=-ve
  • No change occurs in the specific heat of metal

This is further explained below.

<h3>What is the Specific heat of the metal?</h3>

a )Since the metal of the cup is hot and the water inside is cold, the water's temperature will rise as heat is transferred from the metal to the liquid.

Change in temp is positive

b)

Due to (a), heat is lost from the food to the water in the cup, lowering the metal's temperature.

Temp of metal V, dT=-ve

c)

No change occurs in the specific heat of metal because of its constant property.

Read more about Temperature

brainly.com/question/13439286

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7 0
3 years ago
Read 2 more answers
What volume of water is produced when 38.5 g of ethanol reacts with oxygen at 500°C at 1.75 atm?
tensa zangetsu [6.8K]

Answer:

90.99 or 91.0

Explanation:

Using the balanced equation, you convert 38.5g of ethanol to moles of water. From there, you plug the values into the Ideal Gas Equation: PV=nRT.

Download pdf
3 0
3 years ago
Read 2 more answers
What is the number of moles of potassium chloride present in 148 g of kcl?
OLga [1]
The number of moles of one substance given the amount in mass can be calculated by the use of the molar mass. This is the mass of a compound per 1 mol of the said substance. For, KCl the molar mass is 74.55 g/ mol

148 g / 74.55 g/mol = 2 mol KCl

Hope this answers the question. have a nice day.
3 0
3 years ago
Read 2 more answers
Calculate the electric double layer thickness of a alumina colloid in a dilute (0.1 mol/dm3) CsCI electrolyte solution at 30 °C.
Ad libitum [116K]

Explanation:

The given data is as follows.

    Concentration = 0.1 mol/dm^{3}

                             = 0.1 \frac{mol dm^{3}}{dm^{3}} \frac{10^{3}}{dm^{3}} \times \frac{6.022 \times 10^{23}}{1 mol} ions

                             = 6.022 \times 10^{25} ions/m^{3}

               T = 30^{o}C = (30 + 273) K = 303 K

Formula for electric double layer thickness (\lambda_{D}) is as follows.

            \lambda_{D} = \frac{1}{k} = \sqrt \frac{\varepsilon \varepsilon_{o} K_{g}T}{2 n^{o} z^{2} \varepsilon^{2}}

where, n^{o} = concentration = 6.022 \times 10^{25} ions/m^{3}

Hence, putting the given values into the above equation as follows.

                 \lambda_{D} = \sqrt \frac{\varepsilon \varepsilon_{o} K_{g}T}{2 n^{o} z^{2} \varepsilon^{2}}                    

                          = \sqrt \frac{78 \times 8.854 \times 10^{-12} c^{2}/Jm \times 1.38 \times 10^{-23}J/K \times 303 K}{2 \times 6.022 \times 10^{25} ions/m^{3} \times (1)^{2} \times (1.6 \times 10^{-19}C)^{2}}  

                         = 9.669 \times 10^{-10} m

or,                     = 9.7 A^{o}

                          = 1 nm (approx)

Also, it is known that \lambda_{D} = \sqrt \frac{1}{n^{o}}

Hence, we can conclude that addition of 0.1 mol/dm^{3} of KCl in 0.1 mol/dm^{3} of NaBr "\lambda_{D}" will decrease but not significantly.

7 0
3 years ago
How many Molecules does CH4 Have
valentinak56 [21]

Answer:

The amount of molecules in CH4, also known about methane is simply 0.85 * 6.02210 * 10^23 This amounts to about 5.1 * 10^23

4 0
4 years ago
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