All categories

2 years ago

Can anyone help me if possible?

Chemistry

1 answer:

Studentka2010 [4]2 years ago

6 0

Well since I can't sketch anything up on this app no but it is very simple ask a family member to help sketch it out it won't be hard

You might be interested in

Each of the following organs had a role in excretion, EXCEPT for the _____?

eimsori [14]

Answer:

c. the heart

all the rest actually will excrete, the heart is in a closed system so contributes to excretory organs but doesn't actually do it barring an accident

Explanation:

8 0

3 years ago

Read 2 more answers

Calculate the molality of a 20.0% by mass ammonium sulfate (nh4)2so4 solution. the density of the solution is 1.117 g/ml.

olasank [31]

Hello!

We have the following data:

m1 (solute mass) = 20 % m/m
M1 (Molar mass of solute) (NH4)2 SO4 = ?
m2 (mass of the solvent) = ? (in Kg)

First we find the solute mass (m1), knowing that:

20% m/m = 20g/100mL

20 ------ 100 mL (0,1 L)
y g --------------- 1 L

y = 20/0,1
y = 200 g --> m1 = 200 g

Let's find Solute's Molar Mass, let's see:

M1 of (Nh4)2SO4
N = 2*14 = 28
H = (2*4)*1 = 8
S = 1*32 = 32
O = 4*16 = 64
----------------------
M1 of (Nh4)2SO4 = 28+8+32+64 => M1 = 132 g/mol

We must find the volume of the solvent and therefore its mass (m2), let us see:

d = 1,117 g/mL
m = 200 g
v (volumen of solute) = ?

$d = \dfrac{m}{V} \to V = \dfrac{m}{d}$

$V = \dfrac{200\:\diagup\!\!\!\!g}{1,117\:\diagup\!\!\!\!g/mL} \to V = 179\:mL\:(volumen\:of\:solute)$

The solvent volume will be:

1000 -179 => V = 821 mL (volumen of disolvent)

If: 1 mL = 1g

Then the mass of the solvent is:

m2 (mass of the solvent) = 821 g → m2 (mass of the solvent) = 0,821 Kg

Now, we apply all the data found to the formula of Molality, let us see:

$\omega = \dfrac{m_1}{M_1*m_2}$

$\omega = \dfrac{200}{132*0,821}$

$\omega = \dfrac{200}{108,372}$

$\boxed{\boxed{\omega \approx 1,8\:Molal}}\end{array}}\qquad\checkmark$

_________________________________
_________________________________

Another way to find the answer:

We have the following data:

W (molality) = ? (in molal)
n (number of mols) = ?
m1 (solute mass) = 20 % m/m = 20g/100mL → (in g to 1L) = 200 g
m2 (disolvent mass) the remaining percentage, in the case: 80 % m/m = 800 g → m2 (disolvent mass) = 0,8 Kg
M1 (Molar mass of solute) (NH4)2 SO4
N = 2*14 = 28
H = (2*4)*1 = 8
S = 1*32 = 32
O = 4*16 = 64
----------------------
M1 of (Nh4)2SO4 = 28+8+32+64 => M1 = 132 g/mol

Let's find the number of mols (n), let's see:

 $n = \dfrac{m_1}{M_1}$

$n = \dfrac{200}{132}$

$n \approx 1,5\:mol$

Now, we apply all the data found to the formula of Molality, let us see:

$\omega = \dfrac{n}{m_2}$

$\omega = \dfrac{1,5}{0,8}$

$
\boxed{\boxed{\omega \approx 1,8\:Molal}}\end{array}}\qquad\checkmark$

I hope this helps. =)

7 0

3 years ago

Is there a way u could see if the element is acid,base or salt in the periodic table?

Vsevolod [243]

Answer:

OK i see

Explanation:

5 0

2 years ago

What is reaction equation of AgCl

Len [333]

Answer:

NaCl+AgNo3: reactive

AgCl+NaNo3:product

4 0

3 years ago

Calculate the vapor pressure of a solution prepared by dissolving 0.500 mol of a non-volatile solute in 275 g of hexane (C6H14,

Murljashka [212]

Answer:

The vapor pressure = 345.8 torr

Explanation:

Step 1: Data given

Number of molesof a non-volatile solute = 0.500 moles

mass of hexane = 275 grams

Molar mass of hexane = 86.18 g/mol

Temperature =49.6 °C

P°(hexane) = 400.0 torr at 49.6°C.

Step 2: Calculate moles solvent

moles of solvent = 275 grams / 86.18 g/mol = 3.19 mol

Mol fraction of the solvent = 3.19 moles / (0.500 + 3.19) = 0.8645

Step 3: Calculate the vapor pressure

P = P° * Xsolvent

⇒ with Xsolvent = mol fraction of the solvent = 0.8645

⇒ with P° hexane =400.0 torr

P = 400.0 * 0.8645 = 345.8 torr

The vapor pressure = 345.8 torr

3 0

3 years ago