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Anuta_ua [19.1K]
3 years ago
13

Observe: Air pressure is equal to the weight of a column of air on a particular location. Airpressure is measured in millibars (

mb). Note how the air pressure changes as you move StationB towards the center of the high-pressure system.
A. What do you notice?
B. Why do you think this is called a high-pressure system?
Physics
1 answer:
lesya [120]3 years ago
6 0

Answer:

a) When moving towards a high pressure center the pressure values ​​increase in the equipment

b) This area is called high prison since the weight of the atmosphere on top is maximum

Explanation:

A) A high atmospheric pressure system is an area where the pressure is increasing the maximum value is close to 107 Kpa, the other side as low pressure can have small values ​​85.5 kPa.

When moving towards a high pressure center the pressure values ​​increase in the equipment

B) This area is called high prison since the weight of the atmosphere on top is maximum

in general they are areas of good weather

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A grapefruit has a weight on earth of 4.9 newtons. what is the grapefruit's mass?
abruzzese [7]
The force of gravity is the force with which massively large objects such as the earth attracts another object towards itself. All objects of the earth exert a gravity that is directed towards the center of the earth. Therefore, the force of gravity of the earth is equal to the mass of the object times acceleration due to gravity.  

F = ma
4.9N = m (9.8 m/s^2), note that N (newtons) = kg-m/s^2
<u>m = 0.5 kg</u>
<u>The mass of the object is 0.5kg.</u>
7 0
3 years ago
Calculate the magnitude of the total angular momentum of the woman–disk system. (assume that you can treat the woman as a point.
Mrac [35]
 <span>I of disk = 1/2MR² = (0.5)(230)(4.0)² = 1840 kgm² 
I of disk-woman system = I = 1/2MR² + md² = (50)(4.0)² = 1840 + 800 = 2640 kgm² 
L = Iw = (2640)(0.80)(2π) = 13,270 ≈ = 13,000 kgm²/s ANS

idk I'm just trying</span>
8 0
3 years ago
wo plates with area 6.00×10−3 m2 are separated by a distance of 1.50×10−4 m . If a charge of 5.40×10−8 C is moved from one plate
liq [111]

Answer:

V = 152.542 volts

Explanation:

Given data:

area of plates6.00\times 10^{-3} m^2

distance between the plates is 1.50\times 10^{-4} m

charge = 5.40\times 10^{-8} c

we know that capacitance is given as

C = \frac{\epsilon A}{d}

C = \frac{8.85\times 10^{-12} 6\times 10^{-3}}{1.50\times 10^{-4}}

C = 3.54\times 10^{-10} F

potential difference is given as

V =\frac{Q}{C} = \frac{5.40\times 10^{-8}}{3.54\times 10^{-10}}

V = 152.542 volts

3 0
4 years ago
Beings on spherical asteroid have observed that a large rock is approaching their asteroid in a collision course. At 7514 km fro
luda_lava [24]

Answer:

c. 4.582\times10^{21} kg

Explanation:

r_{i} = Initial distance between asteroid and rock = 7514 km = 7514000 m

r_{f} = Final distance between asteroid and rock = 2823 km = 2823000 m

v_{i} = Initial speed of rock = 136 ms⁻¹

v_{f} = Final speed of rock = 392 ms⁻¹

m = mass of the rock

M = mass of the asteroid

Using conservation of energy

Initial Kinetic energy of rock + Initial gravitational potential energy = Final Kinetic energy of rock + Final gravitational potential energy

(0.5) m v_{i}^{2} - \frac{GMm}{r_{i}} = (0.5) m v_{f}^{2} - \frac{GMm}{r_{f}} \\(0.5) v_{i}^{2} - \frac{GM}{r_{i}} = (0.5) v_{f}^{2} - \frac{GM}{r_{f}} \\(0.5) (136)^{2} - \frac{(6.67\times10^{-11}) M}{(7514000)} = (0.5) (392)^{2} - \frac{(6.67\times10^{-11}) M}{(2823000)} \\M = 4.582\times10^{21} kg

8 0
4 years ago
Hello people ~<br>please help me with this question ^^​
matrenka [14]

Answer:

correct is option c I'm sure

/ 3 ql

Explanation:

p net = q ²+ q² + 2 q cos 60

( equilateral triangle ) 60°

is 3p = 3 q

p= pql

your ans

5 0
3 years ago
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