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horsena [70]
3 years ago
15

The back wall of an auditorium is 30.0 m from the stage. If you are seated in the middle row, how much time elapses between a so

und from the stage reaching your ear directly and the same sound reaching your ear after reflecting from the back wall?
Physics
1 answer:
Kipish [7]3 years ago
4 0

Answer:

<h2>0.0875 sec</h2>

Explanation:

Using the relationship to calculate the time that elapse 2x = vt

x = distance between the source and the reflector

v is the velocity of sound in air

t = time elapsed

Given x = 30.0m and v = 343m/s

substituting the values into the formula above to get the total time elapsed t;

t = 2x/v

t = 2(30)/343

t= 60/343

t = 0.175sec

If you are seated in the middle row, the time that will elapse between the sound from the stage reaching your ear directly will be;

0.175/2 = 0.0875 secs

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Answer:

a. F = Qs/2ε₀[1 - z/√(z² + R²)] b.  h =  (1 - 2mgε₀/Qs)R/√[1 - (1 - 2mgε₀/Qs)²]

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cross-multiplying, we have

h² = (1 - 2mgε₀/Qs)²(h² + R²)

expanding the bracket, we have

h² = (1 - 2mgε₀/Qs)²h² + (1 - 2mgε₀/Qs)²R²

collecting like terms, we have

h² - (1 - 2mgε₀/Qs)²h² = (1 - 2mgε₀/Qs)²R²

Factorizing, we have

[1 - (1 - 2mgε₀/Qs)²]h² = (1 - 2mgε₀/Qs)²R²

So, h² =  (1 - 2mgε₀/Qs)²R²/[1 - (1 - 2mgε₀/Qs)²]

taking square-root of both sides, we have

√h² =  √[(1 - 2mgε₀/Qs)²R²/[1 - (1 - 2mgε₀/Qs)²]]

h =  (1 - 2mgε₀/Qs)R/√[1 - (1 - 2mgε₀/Qs)²]

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