Answer:
273.15 dat is the answer im pretty sure
Given:
The force of attraction is F = 48.1 N
The separation between the charges is
Also, the magnitude of charge q1 = q2 = q.
To find the magnitude of charge.
Explanation:
The magnitude of charge can be calculated by the formula
Here, k is the Coulomb's constant whose value is
On substituting the values, the magnitude of charge will be
Thus, the magnitude of each charge is 9.91 x 10^(-4) micro Coulombs.
I think it might be a or d i hope i have helped :)
Answer:
B) Yes, but only those electrons with energy greater than the potential difference established between the grid and the collector will reach the collector.
Explanation:
In the case when the collector would held at a negative voltage i.e. small with regard to grid So yes the accelerated electrons would be reach to the collecting plate as the kinetic energy would be more than the potential energy that because of negative potential
so according to the given situation, the option b is correct
And, the rest of the options are wrong
The Sun's magnetic field goes through a cycle, called the solar cycle. Every 11 years or so, the Sun's magnetic field completely flips. This means that the Sun's north and south poles switch places. Then it takes about another 11 years for the Sun's north and south poles to flip back again.
