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horsena [70]
3 years ago
15

The back wall of an auditorium is 30.0 m from the stage. If you are seated in the middle row, how much time elapses between a so

und from the stage reaching your ear directly and the same sound reaching your ear after reflecting from the back wall?
Physics
1 answer:
Kipish [7]3 years ago
4 0

Answer:

<h2>0.0875 sec</h2>

Explanation:

Using the relationship to calculate the time that elapse 2x = vt

x = distance between the source and the reflector

v is the velocity of sound in air

t = time elapsed

Given x = 30.0m and v = 343m/s

substituting the values into the formula above to get the total time elapsed t;

t = 2x/v

t = 2(30)/343

t= 60/343

t = 0.175sec

If you are seated in the middle row, the time that will elapse between the sound from the stage reaching your ear directly will be;

0.175/2 = 0.0875 secs

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Explanation:

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using vector notation,Let use consider the force on the lower left corner of the mass due to the upper left side of the mass is

F_{12} =\frac{Gm^{2}}{r^{2} }j\\

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The force on the lower left corner of the mass due to the upper right side of the mass is

F_{13} =\frac{Gm^{2}}{d^{2} }cos\alpha i +\frac{Gm^{2}}{d^{2} }sin\alpha j\\

The net force can be express as

F=\frac{Gm^{2}}{r^{2} }j +\frac{Gm^{2}}{r^{2} }i +\frac{Gm^{2}}{d^{2} }cos\alpha i +\frac{Gm^{2}}{d^{2} }sin\alpha j\\\\F=Gm^{2}[\frac{1}{r^{2}}+ \frac{1}{d^{2}cos\alpha }]i + Gm^{2}[\frac{1}{r^{2}}+ \frac{1}{d^{2}sin\alpha }]j\\\alpha=45^{0}, G=6.67*10^{-11}Nmkg^{-2}

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