1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
ipn [44]
3 years ago
9

A string tied between two post is oscillating at 3Hz. A student determines the standing waves have a length of 4 meters. What is

the velocity of the wave?
Physics
1 answer:
torisob [31]3 years ago
8 0

Answer:

12 m/s

Explanation:

Standing waves are waves that are formed between two fixed points in space, so they cannot propagate, but they are just oscillations about a fixed points. Examples of standing waves are the waves in a string.

The relationship between wavelength, frequency and speed of a wave is given by the wave equation:

v=f \lambda

where

v is the speed of the wave

f is its frequency

\lambda is its wavelength

For the standing wave in this problem we have:

f = 3 Hz is the frequency of the wave

\lambda=4 m is the wavelength

Solving for v, we find the velocity of the wave:

v=(3)(4)=12 m/s

You might be interested in
) By observing that the centripetal acceleration of the Moon around the Earth is ac = 2.7 × 10-3 m/s2, what is the gravitatonal
Sedbober [7]

Answer:

G = 6,786 10⁻¹¹ m³ / s² kg

Explanation:

The law of universal gravitation is

         F = G m M/ r²

Where G is the gravitational constant, m and M are the masses of the bodies and r is the distance from their centers

Let's use Newton's second law

         F = m a

The acceleration is centripetal

          a = a_{c}  

We replace

         G m M / r² = m  a_{c}  

         G =  a_{c}   r² / M

Let's replace and calculate

         G = 2.7 10⁻³ (3.88 10⁸)² / 5.99 10²⁴

         G = 6,786 10⁻¹¹ m³ / s² kg

Let's perform a dimensional analysis

[N m²/kg²] = [kg m/s²   m² / kg²] = [m³ / s² kg]

4 0
3 years ago
The Franck-Hertz experiment involved shooting electrons into a low-density gas of mercury atoms and observing discrete amounts o
Anuta_ua [19.1K]

Answer:

the final kinetic energy is 0.9eV

Explanation:

To find the kinetic energy of the electron just after the collision with hydrogen atoms you take into account that the energy of the electron in the hydrogen atoms are given by the expression:

E_n=\frac{-13.6eV}{n^2}

you can assume that the shot electron excites the electron of the hydrogen atom to the first excited state, that is

E_{n_2-n_1}=-13.6eV[\frac{1}{n_2^2}-\frac{1}{n_1^2}]\\\\E_{2-1}=-13.6eV[\frac{1}{2^2}-\frac{1}{1}]=-10.2eV

-10.2eV is the energy that the shot electron losses in the excitation of the electron of the hydrogen atom. Hence, the final kinetic energy of the shot electron after it has given -10.2eV of its energy is:

E_{k}=11.1eV-10.2eV=0.9eV

6 0
3 years ago
Aluminum allows for the flow of electrons, while glass does not. Would an aluminum wire surrounded by glass be an effective desi
pantera1 [17]

answer

no

Explanation:

I do not think that I would because even though its a conductor in the insulator I think it would insulate it before it will work (not sure if that makes sense)

3 0
2 years ago
Suppose that placing 0.3 inch of lead in front of a gamma source reduces the count rate from 1045 cps to 573 cps. What is um^-1
Ainat [17]

Answer:

14.49 g/cm²

Explanation:

I = Io e^-(ux)

Where:

I = 573

Io = 1045

x = 0.3 inches and

rho = 11.4g/cm^3

Using the conversion constant

1 inch = 2.54 cm;

0.3 inches = 0.3 * 2.54 cm

0.3 inches = 0.762 cm

I/Io = e^-(ux), or say

Io/I = e^(ux), taking the In of both sides

ln(Io/I) = ux, making u subject of formula

u = 1/x * ln(Io/I)

u = 1/0.762 * ln(1045/573)

u = 1.312 * 0.6

u = 0.787

Next, we say that

u/rho = 0.7872/11.4 = 0.069

And finally, we make

1/(u/rho) to be our final answer

Inverse of the answer is = 14.49 g/cm²

Therefore, the um^-1 in g/cm^2? is 14.49

5 0
2 years ago
Where are you most likely to build up enough static charge to receive a
FromTheMoon [43]

You're most likely to build up enough static charge to receive a  shock by walking around in a carpeted restaurant in the desert. (A)

Walking on carpet is the fastest way to accumulate charge, and the dry desert air prevents the charge from dribbling off of you and away.

When I walked on stones in the Sinai Desert, the dry wind with a little bit of sand or dust in it built up enough static charge on me that I got a shock every time I stood less than a foot away from my partner.

I had the same experience a few years later near Ouarzazate in the interior of Morocco.

When you hear people say "the desert is dry", they mean it's <em>DRY !  </em>

6 0
3 years ago
Read 2 more answers
Other questions:
  • Can someone pls do this for me for 20 pts
    12·2 answers
  • You travel 60 meters to the left in 20 seconds and then you travel 60 meters to the right in 30 seconds; what is your average ve
    14·1 answer
  • what is the the wavelength if a wave cycles up and down three times per second and the distance between each wave is 1.7m?
    13·1 answer
  • Explain why people who eat only plants must eat a variety of plants in order to obtain all the nutrients they need
    8·1 answer
  • How does the structure of mitochondrial on affect its structure
    15·1 answer
  • An EM wave has a speed of 3 x 10 ^ 8 m/s and a wavelength of 6 x 10 ^ -7 m. What is the frequency of the wave? 90 Hz 180 Hz 2 x
    8·1 answer
  • Is cosine function always used to find x component velocity in resolving vectors
    5·1 answer
  • HELP: I’ve been stuck on this problem for a while now.
    5·1 answer
  • Drag the tiles to the correct boxes to complete the pairs. Not all tiles will be used. Match the reactants with the products.
    13·1 answer
  • How can tidal force from the moon affect our earth?​
    10·2 answers
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!