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GalinKa [24]
3 years ago
8

Why is pseudo science not real science

Chemistry
1 answer:
lilavasa [31]3 years ago
7 0

Answer:

first question

A) it is not testable

second question

C) chemistry

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Which particles give the nucleus its posyive charge
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Proton gives nucleus positive charge P+
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As the atomic radius_______, electron affinity _______. Select the correct answer below: decreases, decreases increases, decreas
kirza4 [7]
I believe the answer is increases , decreases
6 0
2 years ago
Which element increases its oxidation number in this reaction? 2Na + 2H2O → 2NaOH + H2
sammy [17]

Answer:

Sodium

Explanation:

-Gradpoint

6 0
4 years ago
A 3.4 g sample of sodium hydrogen carbonate is added to a solution of acetic acid weighing 10.9 g. The two substances react, rel
natima [27]

Answer: 2.7 grams

Explanation:

According to the law of conservation of mass, mass can neither be created nor be destroyed. Thus the mass of products has to be equal to the mass of reactants. The number of atoms of each element has to be same on reactant and product side. Thus chemical equations are balanced.

NaHCO_3(aq)+CH_3COOH(aq)\rightarrow CH_3COONa(aq)+H_2O(l)+CO_2(g)

Given: mass of sodium hydrogen carbonate = 3.4 g

mass of acetic acid = 10.9 g

Mass of reactants = mass  of sodium hydrogen carbonate+ mass of acetic acid = 3.4 + 10.9= 14.3 g

Mass of reactants = Mass of products in reaction vessel + mass of carbon dioxide (as it escapes)

Mass of  carbon dioxide = 14.3 - 11.6 =2.7 g

Thus the mass of carbon dioxide released during the reaction is 2.7 grams.

7 0
3 years ago
The molar heat capacity of ethane is represented in the temperature range 298 K to 400 K by the empirical expression Cp,m in J K
BabaBlast [244]

Answer:

-88.66 kJ/mol

Explanation:

The expressions of heat capacity (Cp,m) for C(s) and for H₂(g) are:

C(s):  Cp,m/(J K-1 mol-1) = 16.86 + (4.77T/10³) - (8.54x10⁵/T²)

H₂(g): Cp,m/(J K-1 mol-1) = 27.28 + (3.26T/10³) + (0.50x10⁵/T²)

Cp = A + BT + CT⁻²

For the Kirchoff's Law:

ΔHf = ΔH°f + \int\limits^{T2}_{T1} {DCp(T)} \, dT

Where ΔH°f is the enthalpy at 298 K, T1 is 298 K, T2 is the temperature given (373 K), and DCp is the variation of Cp (products less reactants). ΔH°f  for ethene is -84.68 kJ/mol and the reaction is:

2C(s) + 3H₂(g) → C₂H₆

So, DCp:

dA = A(C₂H₆) - [2xA(C) + 3xA(H₂)] = 14.73 - [2x16.86 + 3x27.28] = -100.83

dB = B(C₂H₆) - [2xB(C) + 3xB(H₂)] = 0.1272 - [2x4.77x10⁻³ + 3x3.26x10⁻³] = 0.10788

dC = C(C₂H₆) - [2xC(C) + 3xC(H₂)] = 0 - (2x(-8.54x10⁵) + 3x0.50x10⁵) = 15.58x10⁵

dCp = -100.83 + 0.10788T + 15.58x10⁵T⁻²

\int\limits^{373}_{298} {-100.83 + 0.10788T + 15.58x10^5T^{-2}} \, dT = -3796.48 J/mol = -3.80 kJ/mol (solved by a graphic calculator)

ΔHf = -84.68 - 3.80

ΔHf = -88.66 kJ/mol

7 0
3 years ago
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