15 because atomic no. is the number of protons
Answer:
Pressure will increase since their is not much room
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Explanation:
Answer:
Incomplete question: A student prepares a 0.54 mM aqueous solution of butanoic acid...
The answer is: The percentage of dissociation is 15.4%
Explanation:
Given:
Ka = 1.51x10⁻⁵
Concentration = 0.54 mM = 0.54x10⁻³M
The reaction is:
C₄H₈O₂ = C₄H₇O₂⁻ + H⁺
I 0.54x10⁻³ 0 0
E 0.54x10⁻³(1-x) 0.54x10⁻³x 0.54x10⁻³x
Where x is the degree of dissociation
![Ka=\frac{[H^{+}][C_{4}H_{7}O_{2}^{-} }{[C_{4}H_{8}O_{2} } \\1.51x10^{-5} =\frac{0.54x10^{-3}x^{2} }{1-x} \\x^{2} +0.028x-0.028=0\\x_{1} =0.154\\x_{2} =-0.182](https://tex.z-dn.net/?f=Ka%3D%5Cfrac%7B%5BH%5E%7B%2B%7D%5D%5BC_%7B4%7DH_%7B7%7DO_%7B2%7D%5E%7B-%7D%20%20%20%20%20%7D%7B%5BC_%7B4%7DH_%7B8%7DO_%7B2%7D%20%20%20%7D%20%5C%5C1.51x10%5E%7B-5%7D%20%3D%5Cfrac%7B0.54x10%5E%7B-3%7Dx%5E%7B2%7D%20%20%7D%7B1-x%7D%20%5C%5Cx%5E%7B2%7D%20%2B0.028x-0.028%3D0%5C%5Cx_%7B1%7D%20%3D0.154%5C%5Cx_%7B2%7D%20%3D-0.182)
We will choose the positive value
x = 0.154
The percentage of dissociation is 15.4%
Answer:
H2SO4 (aq) + 2LiOH (aq) --> Li2SO4 (aq) + 2H20 (l)