Answer:

Explanation:
Given data:
Diffusion constant for nitrogen is 
Diffusion flux 
concentration of nitrogen at high presuure = 2 kg/m^3
location on which nitrogen concentration is 0.5 kg/m^3 ......?
from fick's first law

Take C_A as point on which nitrogen concentration is 2 kg/m^3

Assume X_A is zero at the surface


Answer:
final pressure = 200KPa or 29.138psia
Explanation:
The detailed step by step calculations with appropriate conversion factors applied are as shown in the attachment.
Answer:

Explanation:
<u>Projectile Motion</u>
In projectile motion, there are two separate components of the acceleration, velocity and displacement. The horizontal component has zero acceleration (assuming no friction), and the acceleration in the vertical direction is always the acceleration of gravity. The basic formulas are shown below:

Where
is the angle of launch respect to the positive horizontal direction and Vo is the initial speed.

The horizontal and vertical distances are, respectively:


The total flight time can be found as that when y = 0, i.e. when the object comes back to ground (or launch) level. From the above equation we find

Using this time in the horizontal distance, we find the Range or maximum horizontal distance:

Let's solve for 

This is the general expression to determine the angles at which the projectile can be launched to hit the target. Recall the angle can have to values for fixed positive values of its sine:


Or equivalently:

Given Vo=37 m/s and R=70 m


And
