How does the Ivanpah Solar Plant make electricity?
1 answer:
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Answer:
Estimated number of indigenous faults remaining undetected is 6
Explanation:
The maximum likelihood estimate of indigenous faults is given by,
here,
= the number of unseeded faults = 6
= number of seeded faults = 30
= number of seeded faults found = 15
So NF will be calculated as,
And the estimate of faults remaining is = 12 - 6 = 6
Given:
diameter of sphere, d = 6 inches
radius of sphere, r = = 3 inches
density, = 493 lbm/
S.G = 1.0027
g = 9.8 m/ = 386.22 inch/
Solution:
Using the formula for terminal velocity,
=
(1)
where,
V = volume of sphere
= drag coefficient
Now,
Surface area of sphere, A =
Volume of sphere, V =
Using the above formulae in eqn (1):
=
=
=
Therefore, terminal velcity is given by:
=
inch/sec
The image is missing, so i have attached it.
Answer:
A) P = 65.11 KN
B) Q = 30 KN
Explanation:
We are given;
The end reaction of the beam; F = 100KN
Coefficient of static friction between two steel surfaces;μ_ss = 0.3
Coefficient of static friction between steel and concrete;μ_sc = 0.6
So, F1 = μ_ss•F =0.3 x 100 = 30 KN
F2 = μ_ss•N_EF = 0.3N_EF
From the screen shot, we see that the angle is 12°
Sum of forces in the Y-direction gives;
F2•sin12 - N_EF•cos12 + 100 = 0
Rearranging gives;
N_EF•cos12 - F2•sin12 = 100
Let's put 0.3N_EF for F2 to give;
N_EF•cos12 - 0.3N_EF•sin12 = 100
Thus;
N_EF(0.9158) - 0.1247 = 100
N_EF(0.9781) = 100 + 0.1247
N_EF = 100.1247/0.9158
N_EF = 109.33 KN
Thus, F2 = 0.3N_EF = 0.3 x 109.33 = 32.8 KN
Wedge will move if;
P = (F1 + F2cos12 + N_EFsin12)
Thus;
P = 10 + (32.8 x 0.9781) + (109.33 x 0.2079)
P ≥ 65.11 KN
B) For static equilibrium, Q = F1
Thus, Q = 30 KN
