Answer:
See Explaination
Explanation:
// use the `timescale directive which u have used in ur testbench here
module FA1(a,b,cin,s,cout);
input a,b,cin;
output s,cout;
wire s1,c1,c2;
assign s1= #4 a ^ b;
assign s= #4 s1 ^ cin;
assign c1= #2 a & b;
assign c2= #2 s1 & cin;
assign cout= #3 c1 | c2;
endmodule
Answer: The size of the ion and the charge of the ion are the factors that affect solubility in water.
Explanation:
Lead lose electrons to become cations. Compounds with small ions tend to be less soluble than compounds with large ions. Large ions have higher solubility. This is because small ions are closely packed so it is difficult for water to break them apart.
Compounds with small ions seemingly have less solubility than those with large ions. The ions in the compound attract each other, and the water molecules attract the ions. Compounds would be soluble in water If the water molecules have a greater or higher attraction to the ions than ions have for each other.
Answer:
option (a)
Explanation:
t = 5 sec, α = 2 rad/s^2, f0 = 20 rpm = 20 / 60 rps
Use second equation of motion for rotational motion
θ = ω0 x t + 1/2 α t^2
θ = 2 x 3.14 x 5 x 20 / 60 + 0.5 x 2 x 5 x 5
θ = 10.47 + 25 = 35.47 rad
Number of revolution = 35.47 / (2 x 3.14) = 5.65
Answer:
Explanation:
See the attached picture for detailed answer.
Answer:
transfer function from R(s) to E(s) and determine the steady-state error (ess) for a unit-step reference input (c) Select the system parameters (k, kP, kI) such that the closed-loop system has damping coefficient ζ = 0.707 Figure Control system diagram.
Explanation:
hope this helps
