<span>By algebra, d = [(v_f^2) - (v_i^2)]/2a.
Thus, d = [(0^2)-(15^2)]/(2*-7)
d = [0-(225)]/(-14)
d = 225/14
d = 16.0714 m
With 2 significant figures in the problem, the car travels 16 meters during deceleration.</span>
The answer is D) Velocity
Answer:
-67,500 kgm/s
Explanation:
1300 * 20 + 1100 * (-85) = -67,500 kgm/s
Answer:
Velocity,v = 0.323 m/s
Explanation:
The acceleration of a particle is given by :

b = 0.8 m when x = 0
Since,

![\dfrac{v^2}{2}=-[0.1x-0.8cos\dfrac{x}{0.8}]+c](https://tex.z-dn.net/?f=%5Cdfrac%7Bv%5E2%7D%7B2%7D%3D-%5B0.1x-0.8cos%5Cdfrac%7Bx%7D%7B0.8%7D%5D%2Bc)
At x = 0, v = 1 m/s


![\dfrac{v^2}{2}=-[0.1x-0.8cos\dfrac{x}{0.8}]-0.3](https://tex.z-dn.net/?f=%5Cdfrac%7Bv%5E2%7D%7B2%7D%3D-%5B0.1x-0.8cos%5Cdfrac%7Bx%7D%7B0.8%7D%5D-0.3)
At x = -1 m


v = 0.323 m/s
So, the velocity of the particle is 0.323 m/s. Hence, this is the required solution.