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natali 33 [55]
3 years ago
13

The vitamin A molecule has the formula C20H30O, and a molecule of vitamin A2 has the formula C20H28O. Deter- mine how many moles

of vitamin A2 contain the same number of atoms as 1.000 mol vitamin A.
Chemistry
1 answer:
natta225 [31]3 years ago
4 0

Answer:

1.04 moles of vitamin A2 contain the same number of atoms as 1.000 mol vitamin A

Explanation:

Step 1: Data given

Vitamin A = C20H30O

Vitamin A2 = C20H28O

Step 2: Determine the atoms in vitamin A

Vitamin A has 20 C atoms and 30 H atoms and 1 O-atom

In total we have 51 atoms in vitamin A

Step 3: Calculate numbers of atom in 1 mol

1 mol contains 6.022 * 10^23

For 51 atoms = 51 * 6.022*10^23 = 306 *10^23

Step 4: Determine atoms in vitamin A2

Vitamin A2 has 20 C atoms and 28 H atoms and 1 O-atom

In total we have 49 atoms in vitamin A2

Step 5: Calculate molecules A2

Molecules A2 = 306 *10^23  / 49

molecules A2 = 6.24*10^23

Step 6: Calculate how many moles of vitamin A2 contain the same number of atoms as 1.000 mol vitamin A.

n = 6.24*10^23 / 6.022*10^23 = 1.04 mol

1.04 moles of vitamin A2 contain the same number of atoms as 1.000 mol vitamin A

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<h3>Answer:</h3>

\displaystyle 40 \ mol \ Al

<h3>General Formulas and Concepts:</h3>

<u>Math</u>

<u>Pre-Algebra</u>

Order of Operations: BPEMDAS

  1. Brackets
  2. Parenthesis
  3. Exponents
  4. Multiplication
  5. Division
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<u>Chemistry</u>

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<h3>Explanation:</h3>

<u>Step 1: Define</u>

[RxN - Balanced] 2Al₂O₃ → 4Al + 3O₂

[Given] 20 mol Al₂O₃

<u>Step 2: Identify Conversions</u>

[RxN] 2 mol Al₂O₃ → 4 mol Al

<u>Step 3: Stoich</u>

  1. [DA] Set up:                                                                                                     \displaystyle 20 \ mol \ Al_2O_3(\frac{4 \ mol \ Al}{2 \ mol \ Al_2O_3})
  2. [DA] Multiply/Divide [Cancel out units]:                                                         \displaystyle 40 \ mol \ Al

<u>Step 4:Check</u>

<em>Follow sig fig rules and round. We are given 1 sig fig.</em>

Since our final answer already has 1 sig fig, there is no need to round.

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