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natali 33 [55]
3 years ago
13

The vitamin A molecule has the formula C20H30O, and a molecule of vitamin A2 has the formula C20H28O. Deter- mine how many moles

of vitamin A2 contain the same number of atoms as 1.000 mol vitamin A.
Chemistry
1 answer:
natta225 [31]3 years ago
4 0

Answer:

1.04 moles of vitamin A2 contain the same number of atoms as 1.000 mol vitamin A

Explanation:

Step 1: Data given

Vitamin A = C20H30O

Vitamin A2 = C20H28O

Step 2: Determine the atoms in vitamin A

Vitamin A has 20 C atoms and 30 H atoms and 1 O-atom

In total we have 51 atoms in vitamin A

Step 3: Calculate numbers of atom in 1 mol

1 mol contains 6.022 * 10^23

For 51 atoms = 51 * 6.022*10^23 = 306 *10^23

Step 4: Determine atoms in vitamin A2

Vitamin A2 has 20 C atoms and 28 H atoms and 1 O-atom

In total we have 49 atoms in vitamin A2

Step 5: Calculate molecules A2

Molecules A2 = 306 *10^23  / 49

molecules A2 = 6.24*10^23

Step 6: Calculate how many moles of vitamin A2 contain the same number of atoms as 1.000 mol vitamin A.

n = 6.24*10^23 / 6.022*10^23 = 1.04 mol

1.04 moles of vitamin A2 contain the same number of atoms as 1.000 mol vitamin A

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What is the mass of 4.99×1021 platinum atoms?
charle [14.2K]

Answer:

\boxed {\boxed {\sf 1.62 \ g \ Pt}}

Explanation:

We are asked to find the mass of a number of platinum (Pt) atoms.

<h3>1. Convert Atoms to Moles </h3>

First, we convert atoms to moles using Avogadro's Number or 6.022 × 10²³. This is the number of particles (atoms, molecules, formula units, etc.) in 1 mole of a substance. In this case, the particles are platinum atoms.

We will convert using dimensional analysis so we set up a ratio using the information we know (6.022 × 10²³ platinum atoms in 1 mole of platinum).

\frac {6.022 \times 10^{23} \ atoms \ Pt}{ 1 \ mol \ Pt}

We are converting 4.99 ×10²¹ atoms of Pt to moles of Pt, so we multiply by this value.

4.99 \times 10^{21} \ atoms \ Pt *\frac {6.022 \times 10^{23} \ atoms \ Pt}{ 1 \ mol \ Pt}

Flip the ratio so the units of atoms of platinum cancel.

4.99 \times 10^{21} \ atoms \ Pt *\frac { 1 \ mol \ Pt}{6.022 \times 10^{23} \ atoms \ Pt}

4.99 \times 10^{21} *\frac { 1 \ mol \ Pt}{6.022 \times 10^{23}}

\frac { 4.99 \times 10^{21}}{6.022 \times 10^{23}} \ mol \ Pt

Divide.

0.008286283627 \ mol \ Pt

<h3>2. Convert Moles to Grams </h3>

Next, we convert moles to grams using the molar mass. This is the mass of 1 mole of a substance. This is found on the Periodic Table because it is equivalent to the atomic mass, but the units are grams per mole instead of atomic mass units. Look up platinum's molar mass.

  • Pt: 195.08 g/mol

Set up another ratio using this new information (195.08 grams of Pt in 1 mole of Pt).

\frac {195.08 \ g \ Pt}{ 1 \ mol \ Pt}

Multiply by the number of moles we just calculated.

0.008286283627 \ mol \ Pt*\frac {195.08 \ g \ Pt}{ 1 \ mol \ Pt}

The units of moles of platinum cancel.

0.008286283627*\frac {195.08 \ g \ Pt}{ 1 }

0.008286283627* {195.08 \ g \ Pt}

1.61648821\ g \ Pt

<h3>3. Round</h3>

The original measurement of atoms ( 4.99 ×10²¹ ) has 3 significant figures, so our answer must have the same. For the number we found, that is the hundredth place. The 6 in the thousandth place tells us to round the 1 up to a 2.

1.62 \ g \ Pt

There are approximately <u>1.62 grams of platinum</u> in 4.99 ×10²¹ atoms of platinum.

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