Answer:
CH4(g) + Cl2(g) → CH3(g) + HCl(g) and the rate rule is k1 = [CH4][Cl2]
Explanation:
Firstly, we must remember that the substitution reaction between halogens and alkanes to yield halogenoalkanes does not proceed by ionic mechanism rather it proceeds by free radical mechanism.
Now, if we look at the rate determining step as shown in the question, the elementary reaction equation of that step is not balanced.
Hence, the correct elementary reaction equation for the rate determining step and the rate law is; CH4(g) + Cl2(g) → CH3(g) + HCl(g) and the rate rule is k1 = [CH4][Cl2]
Answer:
Science. Chemistry. Chemistry questions and answers. How many equivalents of Mg2+ are present in a solution that contains 2.65 moles of Mg2+ ? Express your answer using three …
Expert Answer. 100% (5 ratings) Number of equivalents of an ion …. View the full answer. Transcribed image text: Question 4 (0.5 points) How many equivalents of Mg2+ are present in …
how many equivalents of Mg2+ are present in a solution that contains 2.75 mol of Mg2+?
A:
5.50 eq
Explanation:
The density of gold is 19.3 g/cm³
Ag= silver
Au= gold.
density (Ag)=10.5 g/cm³.
density (Au)=19.3 g/cm³
We have to calculate the mass of 5 cm³ silver:
10.5 g---------------------1 cm³
x--------------------------- 5 cm³
x=(10.5 g * 5 cm³) / 1cm³ ≈52.5 g
And we have to calculate the mass of 5 g gold.
19.3 g------------------------1 cm³
x-------------------------------5 cm³
x=(19.3 g * 5 cm³) / 1cm³≈96.5 g
Then 5 cm³ silver are 52.5 g of mass, and 5 cm³ gold are 96.5 g of mass, therefore, gold would have a greater mass than silver.
answer:5 cm³ gold would have a greater mass than 5 cm³ silver.
Answer:
Nothing will happen as long as the magnitude of charges remains same...
Explanation:
We know that protons are 1836 times more massive than electrons but they have same magnitude of charge overall. So, if we reverse the polarities the system would still be stable as long as the magnitudes of charges are stable and vice versa.
Answer:
yes
Explanation:
because it is used in electrical conduct.
m not sure
