Answer:
Total work done is 2606.08 J.
Explanation:
Given :
Mass of box , m = 23 kg .
Force applied , F = 100 N .
Angle from horizon , .
Coefficient of kinetic friction , .
Distance travelled by box , d = 34 m .
Now ,
Total work done = work done by boy + work done by friction.
Hence , this is the required solution.
D would be correct.
Have a merry Christmas!
Answer:
distance fallen = 122.5 m
speed = 49 m/s
Explanation:
Δd = vi*t - 0.5at^2
Δd = 0 - 0.5(9.8)(5^2)
Δd = -122.5 (i.e. 122.5m down)
a = (vf - vi) / t
9.8 = (vf - 0) / 5
vf = 49
Answer:
Because it can easily resist air resistance.
Explanation:
Since air resistance is not negligible, the crumpled paper will reach the ground first because it can easily resist air resistance surrounding it compare to the un-crumpled one that will be influenced by the air thereby causing the un-crumpled paper to spend more time in the air
Answer:
Temperature=3.86*10^7K
V1=1.4
Explanation:
Deuterium (2H), when heated to sufficiently high tempera- ture, undergoes a nuclear fusion reaction that results in the production of helium. The reaction proceeds rapidly at a temperature, T, at which the average kinetic energy of the deuterium atoms is 8 × 10216 J. (At this temperature, deu- terium molecules dissociate completely into deuterium atoms.)
(a) Calculate T in kelvins (atomic mass of 2H 5 2.015).
(b) For the fusion reaction to occur with ordinary H atoms, the average energy of the atoms must be about 32 × 10216 J. By what factor does the average speed of the 1H atoms differ from that of the 2H atoms of part (a)?
k.E =3/2kT
K.E is the kinetic energy
k=boltzmann constant
T=Temperature in kelvin
juxtaposing the given values we have
T=2(KE)/3k
T=2*8*10^-16/(3*1.38*10^-23)
T=3.86*10^7K
Temperature=3.86*10^7K
b. average speed V=
R is the gas constant
T absolute temperature in kelvin
M molar mass
since R.T,PI are constant
we are comparing between hydrogen and helium particles
V=
V1/V2=
V1=V2
V1=V2* 1.4
V1=1.4