Answer:
CH₂ ; 67.1 %
Explanation:
To determine the empirical formula we need to find what the mole ratio is in whole numbers of the atoms in the compound. To do that we will first need the atomic weights of C and H and then perform our calculation
Assume 100 grams of the compound.
# mol C = 85.7 g / 12.01 g/mol = 7.14 mol
# mol H = 14.3 g / 1.008 g/mol = 14.19 mol
The proportion is 14.9 mol H/ 7.14 mol C = 2 mol H/ 1 mol C
So the empirical formula is CH₂
For the second part we will need to first calculate the theoretical yield for the 12.03 g NaBH₄ reacted and then calculate the percent yield given the 0.295 g B₂H₆ produced.
We need to calculate the moles of NaBH₄ ( M.W = 37.83 g/mol )
1.203 g NaBH₄ / 37.83 g/mol = 0.0318 mol
Theoretical yield from balanced chemical equation:
0.0318 mol NaBH₄ x 1 mol B₂H₆ / mol NaBH₄ = 0.0159 mol B₂H₆
Theoretical mass yield B₂H₆ = 0.0159 mol x 27.66 g/ mol = 0.440 g
% yield = 0.295 g/ 0.440 g x 100 = 67.1 %
A thick liquid could be one property or its white.....
Answer:
The answer is
<h2>155 g</h2>
Explanation:
The mass of a substance when given the density and volume can be found by using the formula
<h3>mass = Density × volume</h3>
From the question
volume of bromine = 50 mL
density = 3.10 g/cm³
It's mass is
mass = 50 × 3.10
We have the final answer as
<h3>155 g</h3>
Hope this<u> </u>helps you
Answer:
a
Explanation:
got it right in study island xD
Answer is: a possible identity for the unknown compound is C₃H₈.
m(binary compound) = 10.0 g.
m(H₂O) = 16.3 g; mass of water.
M(O₂) = 32 g/mol; molar mass of oxygen.
M(binary compound) = 1.38 · 32 g/mol.
M(binary compound) = 44.16 g/mol.
n(binary compound) = 10 g ÷ 44.16 g/mol.
n(binary compound) = 0.225 mol; amount of substance.
n(H₂O) = 16.3 g ÷ 18 g/mol.
n(H₂O) = 0.9 mol; amount of water.
m(H₂O) : n(binary compound) = 0.9 mol ÷ 0.225 mol.
m(H₂O) : n(binary compound) = 4 : 1.
Unknown cpmpound has 4 times more hydrogen than water, it has 8 hydrogen atoms.
Second element in compound is carbon:
M(X) = 44.16 g/mol - 8 · 1.01 g/mol.
M(X) = 36.08 g/mol ÷ 3.
M(C) = 12.01 g/mol.
