1. I think a drum would be the easiest instrument to explain. You can vary the pitch and loudness by hitting it with different intensities or at different points or angles.
PS. I'm not talking about a drumset. I'm talking about an ordinary drum.
2. Different types of instruments sound different even though they play the same notes because they use different mechanisms for producing sound.
Answer:
In space we feel weightlessness because the earth's gravity has less effect on us. The Earth's gravitational attraction at those altitudes is only about 11% less than it is at the Earth's surface. If you had a ladder that could reach as high as the shuttle's orbit, your weight would be 11% less at the top.
Explanation:
Hope this helps:)
In a free body diagram for an object projected upwards;
- the acceleration due to gravity on the object is always directed downwards.
- the velocity of the object is always in the direction of the object's motion.
An object projected upwards is subjected to influence of acceleration due to gravity.
As the object accelerates upwards, its velocity decreases until the object reaches maximum height where its velocity becomes zero and as the object descends its velocity increases, which eventually becomes maximum before the object hits the ground.
To construct a free body diagram for this motion, we consider the following;
- the acceleration due to gravity on the object is always directed downwards
- the velocity of the object is always in the direction of the object's motion.
<u>For instance:</u>
upward motion for velocity ↑ downward motion for velocity ↓
↑ ↓
↑ ↓
acceleration due to gravity ↓
↓
↓
Learn more here: brainly.com/question/13235430
If you mean S is the distance then it is true
Velocity = Distance / time
To develop this problem it is necessary to apply the concepts given in the balance of forces for the tangential force and the centripetal force. An easy way to detail this problem is through a free body diagram that describes the behavior of the body and the forces to which it is subject.
PART A) Normal Force.
![F_n = \frac{mv^2}{r}](https://tex.z-dn.net/?f=F_n%20%3D%20%5Cfrac%7Bmv%5E2%7D%7Br%7D)
![N+mgcos\theta = \frac{mv^2}{r}](https://tex.z-dn.net/?f=N%2Bmgcos%5Ctheta%20%3D%20%5Cfrac%7Bmv%5E2%7D%7Br%7D)
Here,
Normal reaction of the ring is N and velocity of the ring is v
![N+mgcos\theta = \frac{mv^2}{r}](https://tex.z-dn.net/?f=N%2Bmgcos%5Ctheta%20%3D%20%5Cfrac%7Bmv%5E2%7D%7Br%7D)
![N+Wcos\theta = \frac{W}{g} (\frac{v^2}{r})](https://tex.z-dn.net/?f=N%2BWcos%5Ctheta%20%3D%20%5Cfrac%7BW%7D%7Bg%7D%20%28%5Cfrac%7Bv%5E2%7D%7Br%7D%29)
![N+2cos30\° = \frac{2}{32.2}*\frac{10^2}{2}](https://tex.z-dn.net/?f=N%2B2cos30%5C%C2%B0%20%3D%20%5Cfrac%7B2%7D%7B32.2%7D%2A%5Cfrac%7B10%5E2%7D%7B2%7D)
![N = 1.374lb](https://tex.z-dn.net/?f=N%20%3D%201.374lb)
PART B) Acceleration
![F_t = ma_t](https://tex.z-dn.net/?f=F_t%20%3D%20ma_t)
![-mgsin\theta = ma_t](https://tex.z-dn.net/?f=-mgsin%5Ctheta%20%3D%20ma_t)
![-W sin\theta = \frac{W}{g} a_t](https://tex.z-dn.net/?f=-W%20sin%5Ctheta%20%3D%20%5Cfrac%7BW%7D%7Bg%7D%20a_t)
![-2Sin30\° = (\frac{2}{32.2})a_t](https://tex.z-dn.net/?f=-2Sin30%5C%C2%B0%20%3D%20%28%5Cfrac%7B2%7D%7B32.2%7D%29a_t)
![a_T = -16.10ft/s^2](https://tex.z-dn.net/?f=a_T%20%3D%20-16.10ft%2Fs%5E2)
Negative symbol indicates deceleration.
<em>NOTE: For the problem, the graph in which the turning radius and the angle of suspension was specified was not supplied. A graphic that matches the description given by the problem is attached.</em>