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Fed [463]
3 years ago
12

Unit Test

Physics
1 answer:
irina [24]3 years ago
6 0

Neutrons

Explanation:

Atoms of the same elements are called isotopes. They differ from other atoms in the number of neutrons they posses. They share the same chemical properties but only differ with regards to their mass number.

  • Isotopy is a phenomenon whereby an atom of an element exist in more than one form but they have the same atomic number.
  • Atoms of such element only differ in the number of neutrons they contain.
  • Since the mass number of an atom is the sum of protons and neutrons, they differ in this number too
  • Isotopes have the same chemical properties.

learn more:

Isotopes brainly.com/question/10862182

#learnwithBrainly

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How does a vacuum flask keep drinks hot? Explain in terms of conduction, convection and radiation.
Flura [38]
Vacum flask has inner layer of glass and outer body of plastic.the glass has a reflective metal layer..when a hot drink is poured into the flask it prevents conduction.tight lid stops the convection.when radiation tries to leave the hot drink the reflective layer of the glass reflects it back so no heat can escape.
4 0
3 years ago
A force of 20 N produces an acceleration of 10 m/s² in mass m1 and an acceleration of 5 m/s² in
Scrat [10]

Explanation:

F = 20N m= m1 a=10m/s²

m=m2 a=5m/s²

F = ma

<u>for the first one</u><u>:</u><u> </u>

f=m1 × a

20 = m1 ×10

20=10m1

m1=20/10

m1=2

<u>for</u><u> </u><u>the</u><u> </u><u>second</u><u> </u><u>one</u><u> </u><u>:</u>

f=m2×a

20=m2×5

m2= 20/5

m2= 4

since F=ma

F=(m1+m2) ×a

F =(4+2)×a

F =6×a

F=20(from the question above )

20=6×a

a=20/6

a=3.33

8 0
3 years ago
Read 2 more answers
The near point of an eye is 48.5 cm. A corrective lens is to be used to allow this eye to focus clearly on objects at the distan
Masteriza [31]

Answer:

The focal length of the lens should be -51.5 cm (a concave lens).

Explanation:

The purpose of the lens is to make objects at 48.5 cm appear at the healthy near point. The healthy near point is 25.0 cm.

We use the lens formula

\dfrac{1}{f} = \dfrac{1}{u} + \dfrac{1}{v}

where <em>f</em> = focal length, <em>u</em> = object distance and <em>v</em> = image distance.

In this case, <em>u</em> = 48.5 cm and <em>v</em> = -25.0 cm.

<em>v</em> is negative because the image is virtual an not real. (Here, we are using the real-is-positive sign convention)

\dfrac{1}{f} = \dfrac{1}{48.5} + \dfrac{1}{-25.0} = -\dfrac{23.5}{1212.5}

f = -51.5

The negative sign indicates the lens is concave.

3 0
3 years ago
Which equation would you use to calculate how much work is done in pushing a rock to the edge of the cliff?
Natalka [10]

Answer:

d

Explanation:

d because a b c are energy equation not work

4 0
2 years ago
A small 0.13 kg metal ball is tied to a very light (essentially massless) string that is 0.70 m long. The string is attached to
beks73 [17]

Answer:

Explanation:

Let l be th length of pendulum

loss of height

= mg ( l - l cos50)

= mg l ( 1-cos50)

1/2 mv² = mgl ( 1-cos50)

v = √[2gl( 1- cos50)]

= √( 2 x 9.8 x .7 x ( 1-cos50)

= 2.2 m / s

speed at the bottom = 2.2 m /s

b )

centripetal acceleration

= v² / r

= 2.2 x 2.2 / .7

= 6.9 m /s²

C )

If T be the tension

T - mg = mv² / r

T = mg + mv² / r

= .13 X 9.8 + .13 X 6.9

= 2.17 N

7 0
3 years ago
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