Answer:
Explanation:
The options is not well presented
This are the options
A. θ = at³ + b
B. θ = at² + bt + c
C. θ = at² — b
D. θ = Sin(at)
So, we want to prove which of the following option have a constant angular acceleration I.e. does not depend on time
Now,
Angular acceleration can be determine using.
α = d²θ / dt²
α = θ''(t)
So, second deferential of each θ(t) will give the angular acceleration
A. θ = at³ + b
dθ/dt = 3at² + 0 = 3at²
d²θ/dt² = 6at
α = d²θ/dt² = 6at
The angular acceleration here still depend on time
B. θ = at² + bt + c
dθ/dt = 2at + b + 0 = 2at + b
d²θ/dt² = 2a + 0 = 2a
α = d²θ/dt² = 2a
Then, the angular acceleration here is constant is "a" is a constant and the angular acceleration is independent on time.
C. θ = at² —b
dθ/dt = 2at — 0 = 2at
d²θ/dt² = 2a
α = d²θ/dt² = 2a
Same as above in B. The angular acceleration here is constant is "a" is a constant and the angular acceleration is independent on time.
D. θ = Sin(at)
dθ/dt = aCos(at)
d²θ/dt² = —a²Sin(at) = —a²θ
α = d²θ/dt² = -a²θ
Since θ is not a constant, then, the angular acceleration is dependent on time and angular displacement
So,
The answer is B and C
We have that Since Cart A spends t=77.5secs and Cart B spends t=50sec
Therefore
The Cart A wins the Race and by 25.5( 77.7-50)secs
From the question we are told
- Two go carts, A and B race each other around a 1.0 km track.
- Go cart A travels at a constant speed of 20.0 m/s.
- Go cart B accelerates uniformly from rest at a rate of 0.333 m/s
For Cart A
Generally the equation for the Velocity is mathematically given as
For Cart B
Generally the Newtons equation for the Motion is mathematically given as
Since
Cart A spends t=77.5secs and Cart B spends t=50sec
Therefore
The Cart A wins the Race and by 25.5( 77.7-50)secs
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Answer:
direct current
Explanation:
it has a direct path to go down to reach the specific point
Answer:
The value is 
Explanation:
From the question we are told that
The focal length of the objective is 
The focal length of the eyepiece is 
The tube length is 
Generally the magnitude of the overall magnification is mathematically represented as
Where 
is the objective magnification which is mathematically represented as
=> 
=> 
is the eyepiece magnification which is mathematically evaluated as
So
