Question

lood flows through a section of a horizontal artery that is partially blocked by a deposit along the artery wall. As a hemoglobin molecule moves from the narrow region into the wider region, its speed changes from v2 = 0.800 m/s to v1 = 0.475 m/s. What is the change in pressure, P1 - P2, that it experiences? The density of blood is 1060 kg/m3.

Answer 1

Answer:

$P_1 - P_2 =219.62\ Pa$

Explanation:

given,

density of blood = 1060 kg/m³

v₂ = 0.800 m/s

v₁ = 0.475 m/s

change in pressure calculation

using Bernoulli's equation

$P_1 +\dfrac{1}{2}\rho v_1^2 = P_2 + \dfrac{1}{2}\rho v_2^2$

both are at same level

$P_1 - P_2 =\dfrac{1}{2}\rho (v_2^2- v_1^2)$

$P_1 - P_2 =\dfrac{1}{2}1060\times (0.8^2- 0.475^2)$

$P_1 - P_2 =219.62\ Pa$

the change in pressure is equal to 219.62 Pa