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Ira Lisetskai [31]
3 years ago
10

The water behind Grand Coulee Dam is 1000 m wide and 200 m deep. Find the hydrostatic force on the back of the dam. (Hint: the t

otal force = average pressure × area)
Physics
1 answer:
Vika [28.1K]3 years ago
7 0

Answer:

The hydro static force on the back of the dam is 1.96\times10^{11}\ N

Explanation:

Given that,

Width b= 1000 m

Depth d= 200 m

We need to calculate the average pressure

Using formula of  average pressure

P_{avg}=\rho\times g\times d_{avg}

Put the value into the formula

P_{avg}=1000\times9.8\times100

P_{avg}=980000\ Pa

We need to calculate  the hydro static force on the back of the dam

Using formula of force

F = P_{avg}\times A

Put the value into the formula

F = 980000\times1000\times200

F=1.96\times10^{11}\ N

Hence, The hydro static force on the back of the dam is 1.96\times10^{11}\ N

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3 years ago
A mass weighing 4 lb stretches a spring 2 in. Suppose that the mass is given an additional 6-in displacement in the positive dir
givi [52]

Answer:

\frac{1}{8} y'' + 2y' + 24y=0

Explanation:

The standard form of the 2nd order differential equation governing the motion of mass-spring system is given by

my'' + \zeta y' + ky=0

Where m is the mass, ζ is the damping constant, and k is the spring constant.

The spring constant k can be found by

w - kL=0

mg - kL=0

4 - k\frac{1}{6}=0

k = 4\times 6 =24

The damping constant can be found by

F = -\zeta y'

6 = 3\zeta

\zeta = \frac{6}{3} = 2

Finally, the mass m can be found by

w = 4

mg=4

m = \frac{4}{g}

Where g is approximately 32 ft/s²

m = \frac{4}{32} = \frac{1}{8}

Therefore, the required differential equation is

my'' + \zeta y' + ky=0

\frac{1}{8} y'' + 2y' + 24y=0

The initial position is

y(0) = \frac{1}{2}

The initial velocity is

y'(0) = 0

6 0
3 years ago
__________ is/are formed between two air masses that have different temperatures. (4 points) A: Wind B:The jet stream C:Clouds D
lidiya [134]
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8 0
3 years ago
Read 2 more answers
What is brownion motion
Alex777 [14]

Answer: Brownion motion is the erratic random movement of microscopic particles in a fluid, as a result of continuous bombardment from molecules of the surrounding medium.

Explanation:

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4 0
4 years ago
The volume occupied by a sample of gas is 480 mL when the pressure is 115 kPa.What pressure must be applied to the gas to make i
balandron [24]

Answer:

The answer is

<h2>84.9 kPa</h2>

Explanation:

Using Boyle's law to find the final pressure

That's

P_1V_1 = P_2V_2

where

P1 is the initial pressure

P2 is the final pressure

V1 is the initial volume

V2 is the final volume

Since we are finding the final pressure

P_2 =  \frac{P_1V_1}{V_2}

From the question

P1 = 115 kPa

V1 = 480 mL

V2 = 650 ml

So we have

P_2 =  \frac{115000 \times 480}{650}  = \frac{55200000}{650}  \\  = 84923.076923...

We have the final answer as

<h3>84.9 kPa</h3>

Hope this helps you

7 0
3 years ago
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